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hejå

  • 2 years ago

hw10 part 3

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  1. Jose.oliveira2
    • 2 years ago
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    H10P3 a) (((j*w*L+R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C))))/((j*w*L + R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C)))+R1)*(R2/(j*w*L + R2))) b) ((j * w * L + R2) * (1 / (j * w * C))) / (j * w * L + R2 + (1 / (j * w * C ))) c) (sqrt (R1/R2 -1)) / (w * R1) d) ((sqrt (R1/R2 -1)) * R2) / w e) Change values in C (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3) f) Change values in D (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3)

  2. chiragsala
    • 2 years ago
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    part e answer is: 1101.175 part f: 55.0587

  3. dubiduba
    • 2 years ago
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    correct is part e anwser is: 889.4pF part f answer is: 44.5uH

  4. acid16
    • 2 years ago
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    Lmatch = sqrt(R1R2 – R2^2)/w and Cmatch = R1R2/(w*sqrt(R1R2 – R2^2))

  5. acid16
    • 2 years ago
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    becarful there are diferent values for someone....

  6. chiragsala
    • 2 years ago
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    @dubiduba we might be having different values for R1 and R2 it all depends on the previous 2 formulas of Lmatch and Cmatch.

  7. Abhaypratap
    • 2 years ago
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    Cmatch = 1/(w*sqrt(R1R2 – R2^2))

  8. Abhaypratap
    • 2 years ago
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    Lmatch = sqrt(R1R2 – R2^2)/w

  9. prit1010
    • 2 years ago
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    Part-1 ?????

  10. hejå
    • 2 years ago
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    confused with the last 2

  11. brunofornari
    • 2 years ago
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    w??

  12. Jose.oliveira2
    • 2 years ago
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    w = 2*pi*f see the question C in Pico F in Micro

  13. chiragsala
    • 2 years ago
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    Finally got the h9p1 completely......guys those who are strugling with h9p1 part e they need to use the formula.with sin term as 1.

  14. vision89
    • 2 years ago
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    H10P3 e &f ans please

  15. Abhaypratap
    • 2 years ago
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    giv me ur question pls

  16. Abhaypratap
    • 2 years ago
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    w = 2*pi*f Cmatch = 1/(w*sqrt(R1R2 – R2^2)) Lmatch = sqrt(R1R2 – R2^2)/w

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