hejå 3 years ago hw10 part 3

1. Jose.oliveira2

H10P3 a) (((j*w*L+R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C))))/((j*w*L + R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C)))+R1)*(R2/(j*w*L + R2))) b) ((j * w * L + R2) * (1 / (j * w * C))) / (j * w * L + R2 + (1 / (j * w * C ))) c) (sqrt (R1/R2 -1)) / (w * R1) d) ((sqrt (R1/R2 -1)) * R2) / w e) Change values in C (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3) f) Change values in D (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3)

2. chiragsala

part e answer is: 1101.175 part f: 55.0587

3. dubiduba

correct is part e anwser is: 889.4pF part f answer is: 44.5uH

4. acid16

Lmatch = sqrt(R1R2 – R2^2)/w and Cmatch = R1R2/(w*sqrt(R1R2 – R2^2))

5. acid16

becarful there are diferent values for someone....

6. chiragsala

@dubiduba we might be having different values for R1 and R2 it all depends on the previous 2 formulas of Lmatch and Cmatch.

7. Abhaypratap

Cmatch = 1/(w*sqrt(R1R2 – R2^2))

8. Abhaypratap

Lmatch = sqrt(R1R2 – R2^2)/w

9. prit1010

Part-1 ?????

10. hejå

confused with the last 2

11. brunofornari

w??

12. Jose.oliveira2

w = 2*pi*f see the question C in Pico F in Micro

13. chiragsala

Finally got the h9p1 completely......guys those who are strugling with h9p1 part e they need to use the formula.with sin term as 1.

14. vision89

15. Abhaypratap

giv me ur question pls

16. Abhaypratap

w = 2*pi*f Cmatch = 1/(w*sqrt(R1R2 – R2^2)) Lmatch = sqrt(R1R2 – R2^2)/w