A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0\[Tan^2x  \cos^2x = 1/\cos^2  1  \cos^2x\]

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1can you rewrite that right side? is that \[\frac 1{cos^2 x  1}  \cos ^2 x\]

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352207602501:dw

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1you know this identity right? \[\sin^2 x = 1  \cos^2 x\]

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1wait..nevermind what i said....

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac 1{\cos^2x}  1  \cos^2 x\] convert to common denominators first \[\implies \frac 1{\cos^2 x}  \frac{\cos^2 x}{\cos^2 x}  \frac{\cos^4 x}{\cos^2 x}\] agree?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0yes :) I was on the right track whew :P

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1now combine the numerators \[\frac{1  \cos^2 x  \cos ^ 4 x}{\cos^2 x}\] is this what you did?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0yes but Instead if making it cos^4x I cancelled out the top bracket Cos^2x with the bottom one...which is probably where I went wrong?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1no. that works too \[\frac{1  \cos^2 x}{\cos^2 x}  \cos^2 x\] yes?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0hmm, why didnt you just totally cancel out the denominator?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0I was left with 1cos^2xcos^2x :S

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1ah. that's different

HorribleAtMath
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352208030577:dw

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0hmm whats the reason I couldnt?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1observe what i did earlier \[\frac 1{\cos^2 x}  1  \cos^2 x \implies \frac 1{\cos^2 x}  \frac{\cos^2 x}{\cos^2 x}  \frac{\cos^4 x}{\cos^2 x}\] each term has its own denominator

HorribleAtMath
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352208100756:dw

HorribleAtMath
 2 years ago
Best ResponseYou've already chosen the best response.0ap calc etcher tell me that

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1if you cancel out the cos^2 x below cos^4 x, you can only do it there, and not in the other terms. make sense?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1so anyway, the RHS simplifies to \[\frac{1  \cos^2 x}{\cos^2 x}  \cos^2 x\] i assume you know how to proceed form tehre?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0should i move to the left side?

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0wo think i got it? L.S) will equel 1cos^2/cos^2x  Cos^2x

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0Ls = Rs Sweet! Thanks for your help! I also found a few more I am having trouble with...this next question has a tan^3x which I haven't used in a while i forget what i can do with it

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1tan^3 x = tan^2 x * tan x

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1or maybe tan^3 x = sin^3 x / cos^3 x

Rosh007
 2 years ago
Best ResponseYou've already chosen the best response.0\[\tan ^{2}x  \cos^{2}x =\frac{1}{ \cos^2(x)} 1 \cos^{2}x \] \[\tan ^{2}x  \cos^{2}x =\frac{(1\cos^{2}x) }{ \cos^2(x)}  \cos^{2}x \] which is \\[\tan ^{2}x =\frac{(1\cos^{2}x) }{ \cos^2(x)} \] which is \[\tan ^{2}x =\frac{(\sin^{2}x) }{ \cos^2(x)}\] which satisfis the relation

Christians4
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks guys, lemme try this other one and i cant get it ill post a new question
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.