Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
\[Tan^2x  \cos^2x = 1/\cos^2  1  \cos^2x\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
can you rewrite that right side? is that \[\frac 1{cos^2 x  1}  \cos ^2 x\]
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352207602501:dw
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
you know this identity right? \[\sin^2 x = 1  \cos^2 x\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
wait..nevermind what i said....
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
alright
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
\[\frac 1{\cos^2x}  1  \cos^2 x\] convert to common denominators first \[\implies \frac 1{\cos^2 x}  \frac{\cos^2 x}{\cos^2 x}  \frac{\cos^4 x}{\cos^2 x}\] agree?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
yes :) I was on the right track whew :P
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
now combine the numerators \[\frac{1  \cos^2 x  \cos ^ 4 x}{\cos^2 x}\] is this what you did?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
yes but Instead if making it cos^4x I cancelled out the top bracket Cos^2x with the bottom one...which is probably where I went wrong?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
no. that works too \[\frac{1  \cos^2 x}{\cos^2 x}  \cos^2 x\] yes?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
hmm, why didnt you just totally cancel out the denominator?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
I was left with 1cos^2xcos^2x :S
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
ah. that's different
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
you can't do that
 2 years ago

HorribleAtMath Group TitleBest ResponseYou've already chosen the best response.0
dw:1352208030577:dw
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
hmm whats the reason I couldnt?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
observe what i did earlier \[\frac 1{\cos^2 x}  1  \cos^2 x \implies \frac 1{\cos^2 x}  \frac{\cos^2 x}{\cos^2 x}  \frac{\cos^4 x}{\cos^2 x}\] each term has its own denominator
 2 years ago

HorribleAtMath Group TitleBest ResponseYou've already chosen the best response.0
dw:1352208100756:dw
 2 years ago

HorribleAtMath Group TitleBest ResponseYou've already chosen the best response.0
ap calc etcher tell me that
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
OH I understand
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
if you cancel out the cos^2 x below cos^4 x, you can only do it there, and not in the other terms. make sense?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
yes! I love you :P
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
so anyway, the RHS simplifies to \[\frac{1  \cos^2 x}{\cos^2 x}  \cos^2 x\] i assume you know how to proceed form tehre?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
should i move to the left side?
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
wo think i got it? L.S) will equel 1cos^2/cos^2x  Cos^2x
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
Ls = Rs Sweet! Thanks for your help! I also found a few more I am having trouble with...this next question has a tan^3x which I haven't used in a while i forget what i can do with it
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
tan^3 x = tan^2 x * tan x
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
that can work
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
or maybe tan^3 x = sin^3 x / cos^3 x
 2 years ago

Rosh007 Group TitleBest ResponseYou've already chosen the best response.0
\[\tan ^{2}x  \cos^{2}x =\frac{1}{ \cos^2(x)} 1 \cos^{2}x \] \[\tan ^{2}x  \cos^{2}x =\frac{(1\cos^{2}x) }{ \cos^2(x)}  \cos^{2}x \] which is \\[\tan ^{2}x =\frac{(1\cos^{2}x) }{ \cos^2(x)} \] which is \[\tan ^{2}x =\frac{(\sin^{2}x) }{ \cos^2(x)}\] which satisfis the relation
 2 years ago

Christians4 Group TitleBest ResponseYou've already chosen the best response.0
Thanks guys, lemme try this other one and i cant get it ill post a new question
 2 years ago

Rosh007 Group TitleBest ResponseYou've already chosen the best response.0
all the best :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.