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DANIEL93
Group Title
single variable calculus . help me friends
find the maclaurine series for
(i) f(x)=1/1−x
 2 years ago
 2 years ago
DANIEL93 Group Title
single variable calculus . help me friends find the maclaurine series for (i) f(x)=1/1−x
 2 years ago
 2 years ago

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klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(\frac1{1x}=1+x+x^2+x^3+..., x<1\)
 2 years ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
can you explain how to get it?
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
It is the sum of the geometric sequence.
 2 years ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
oh.. okay2. how to find taylor series then?
 2 years ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
do you know?
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(f(x)=f(x_0)+f'(x_0)(xx_0)+\frac{f''(xx_0)}{2!}(xx_0)^2+\ldots+\frac{f^{(n)}(x_0)}{n!}(xx_0)^n+\ldots\)
 2 years ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
\[\huge f(x)=\sum_{n=0}^{+\infty} \frac{ f^n(a) }{ n! }(xa)^n\] compute the value of \[\huge f^{(n)}(a)\]
 2 years ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
where f^0(a) is the value of the function, f^1(a) is the value of the first derivative. For the maclaurin series, use a = 0.
 2 years ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
@klimenkov : thank you :D @sirm3d : tHANK yOU :D
 2 years ago
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