DANIEL93
single variable calculus . help me friends
find the maclaurine series for
(i) f(x)=1/1−x



This Question is Closed

klimenkov
Best Response
You've already chosen the best response.
1
\(\frac1{1x}=1+x+x^2+x^3+..., x<1\)

DANIEL93
Best Response
You've already chosen the best response.
0
solution?

klimenkov
Best Response
You've already chosen the best response.
1
Yes.

DANIEL93
Best Response
You've already chosen the best response.
0
can you explain how to get it?

klimenkov
Best Response
You've already chosen the best response.
1
It is the sum of the geometric sequence.

DANIEL93
Best Response
You've already chosen the best response.
0
oh.. okay2. how to find taylor series then?

DANIEL93
Best Response
You've already chosen the best response.
0
do you know?

klimenkov
Best Response
You've already chosen the best response.
1
\(f(x)=f(x_0)+f'(x_0)(xx_0)+\frac{f''(xx_0)}{2!}(xx_0)^2+\ldots+\frac{f^{(n)}(x_0)}{n!}(xx_0)^n+\ldots\)

sirm3d
Best Response
You've already chosen the best response.
0
\[\huge f(x)=\sum_{n=0}^{+\infty} \frac{ f^n(a) }{ n! }(xa)^n\] compute the value of \[\huge f^{(n)}(a)\]

sirm3d
Best Response
You've already chosen the best response.
0
where f^0(a) is the value of the function, f^1(a) is the value of the first derivative. For the maclaurin series, use a = 0.

DANIEL93
Best Response
You've already chosen the best response.
0
@klimenkov : thank you :D
@sirm3d : tHANK yOU :D