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single variable calculus . help me friends find the maclaurine series for (i) f(x)=1/1−x

Mathematics
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\(\frac1{1-x}=1+x+x^2+x^3+..., |x|<1\)
solution?
Yes.

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Other answers:

can you explain how to get it?
It is the sum of the geometric sequence.
oh.. okay2. how to find taylor series then?
do you know?
\(f(x)=f(x_0)+f'(x_0)(x-x_0)+\frac{f''(x-x_0)}{2!}(x-x_0)^2+\ldots+\frac{f^{(n)}(x_0)}{n!}(x-x_0)^n+\ldots\)
\[\huge f(x)=\sum_{n=0}^{+\infty} \frac{ f^n(a) }{ n! }(x-a)^n\] compute the value of \[\huge f^{(n)}(a)\]
where f^0(a) is the value of the function, f^1(a) is the value of the first derivative. For the maclaurin series, use a = 0.
@klimenkov : thank you :D @sirm3d : tHANK yOU :D

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