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DANIEL93
Group Title
single variable calculus . help me friends
find the maclaurine series for
(i) f(x)=1/1−x
 one year ago
 one year ago
DANIEL93 Group Title
single variable calculus . help me friends find the maclaurine series for (i) f(x)=1/1−x
 one year ago
 one year ago

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klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(\frac1{1x}=1+x+x^2+x^3+..., x<1\)
 one year ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
solution?
 one year ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
can you explain how to get it?
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
It is the sum of the geometric sequence.
 one year ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
oh.. okay2. how to find taylor series then?
 one year ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
do you know?
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(f(x)=f(x_0)+f'(x_0)(xx_0)+\frac{f''(xx_0)}{2!}(xx_0)^2+\ldots+\frac{f^{(n)}(x_0)}{n!}(xx_0)^n+\ldots\)
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
\[\huge f(x)=\sum_{n=0}^{+\infty} \frac{ f^n(a) }{ n! }(xa)^n\] compute the value of \[\huge f^{(n)}(a)\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
where f^0(a) is the value of the function, f^1(a) is the value of the first derivative. For the maclaurin series, use a = 0.
 one year ago

DANIEL93 Group TitleBest ResponseYou've already chosen the best response.0
@klimenkov : thank you :D @sirm3d : tHANK yOU :D
 one year ago
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