Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

DANIEL93

  • 3 years ago

single variable calculus . help me friends find the maclaurine series for (i) f(x)=1/1−x

  • This Question is Closed
  1. klimenkov
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\frac1{1-x}=1+x+x^2+x^3+..., |x|<1\)

  2. DANIEL93
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    solution?

  3. klimenkov
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes.

  4. DANIEL93
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you explain how to get it?

  5. klimenkov
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    It is the sum of the geometric sequence.

  6. DANIEL93
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh.. okay2. how to find taylor series then?

  7. DANIEL93
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you know?

  8. klimenkov
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(f(x)=f(x_0)+f'(x_0)(x-x_0)+\frac{f''(x-x_0)}{2!}(x-x_0)^2+\ldots+\frac{f^{(n)}(x_0)}{n!}(x-x_0)^n+\ldots\)

  9. sirm3d
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\huge f(x)=\sum_{n=0}^{+\infty} \frac{ f^n(a) }{ n! }(x-a)^n\] compute the value of \[\huge f^{(n)}(a)\]

  10. sirm3d
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where f^0(a) is the value of the function, f^1(a) is the value of the first derivative. For the maclaurin series, use a = 0.

  11. DANIEL93
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @klimenkov : thank you :D @sirm3d : tHANK yOU :D

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy