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Prove:
(sinx + cosx) (Tan^2x+1/tanx) = 1/cosx + 1/sinx
Picture below for what it looks like properly
 one year ago
 one year ago
Prove: (sinx + cosx) (Tan^2x+1/tanx) = 1/cosx + 1/sinx Picture below for what it looks like properly
 one year ago
 one year ago

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Christians4Best ResponseYou've already chosen the best response.0
tell me if you need clarification i can drop LS and RS
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
hmm seems i really can't figure out what you mean. maybe it's time to show the picture
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
dw:1352211230059:dw
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
dw:1352211285143:dw
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
here's a hint that might help: \[\huge \tan^2 x + 1 = \sec^2 x\] and \[\huge \sec^2 x = \frac1{\cos^2 x}\] try solving it
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
I ended up getting (sinx+cosx) (1/cosxsinx) for my left side
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
How do I prove identities that are like this:
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
1+tanx/1tanx = Tan (x+pi/4)
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
\[\frac{1+\tan(x)}{1\tan(x)}=\tan(x+\frac{\pi}{4})\] I would write each side so that the function tan( ) only contains x and not both x & x+pi/4. You the sum identity for tan. If you don't know it write both sides in terms of sine and cosine. Use the sum identities for them to expand tan(x+pi/4)
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
sum identity for tan?
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
I know the cos and sin ones
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
is it just those over eachother?
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
do u simply mean sinx/cosx?
 one year ago

phiBest ResponseYou've already chosen the best response.1
try using tan = sin/cos and see how it works out
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
alright but on the R.S what do i do with the (x +pi/4)
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
\[\tan(x+\frac{\pi}{4})=\frac{\sin(x+\frac{\pi}{4})}{\cos(x+\frac{\pi}{4})}\] Use sum identity for sine and cosine.
 one year ago

phiBest ResponseYou've already chosen the best response.1
remember sin(a+b)= sin(a)cos(b) + cos(a) sin(b) and cos(a+b)= cos(a)cos(b) sin(a)sin(b)
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
I plugged in the sum identity but i dont know what do to next I have sin and cosx's which i dont know what to do with
 one year ago

phiBest ResponseYou've already chosen the best response.1
write down what you have so far
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
sinxcospi/4 +cpsxsinpi/4 / cospi/4cosx + sinpi/4sinx
 one year ago

phiBest ResponseYou've already chosen the best response.1
pi/4 is 45º it is good to have memorized cos(45) and sin(45)
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
oh i knew that but can i convert it in the eqqn?
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
so i could right 45deg instead of pi/4?
 one year ago

phiBest ResponseYou've already chosen the best response.1
btw, notice that you have the wrong sign in the denominator
 one year ago

phiBest ResponseYou've already chosen the best response.1
pi/4 and 45 mean the same thing.... it matters when using a calculator, or in certain math operations where radians are more useful... but the cos(45º) = cos(pi/4 radians)
 one year ago

phiBest ResponseYou've already chosen the best response.1
just like 1 foot is the same as 12 inches
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
I think i got it, gotta head to class now, ill ask teacher if hes free
 one year ago

Christians4Best ResponseYou've already chosen the best response.0
Thanks for your help
 one year ago
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