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Christians4 Group Title

Prove: (sinx + cosx) (Tan^2x+1/tanx) = 1/cosx + 1/sinx Picture below for what it looks like properly

  • one year ago
  • one year ago

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  1. Christians4 Group Title
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    tell me if you need clarification i can drop LS and RS

    • one year ago
  2. Christians4 Group Title
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    yes your back!

    • one year ago
  3. lgbasallote Group Title
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    hmm seems i really can't figure out what you mean. maybe it's time to show the picture

    • one year ago
  4. Christians4 Group Title
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    |dw:1352211230059:dw|

    • one year ago
  5. Christians4 Group Title
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    |dw:1352211285143:dw|

    • one year ago
  6. lgbasallote Group Title
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    ahh

    • one year ago
  7. lgbasallote Group Title
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    here's a hint that might help: \[\huge \tan^2 x + 1 = \sec^2 x\] and \[\huge \sec^2 x = \frac1{\cos^2 x}\] try solving it

    • one year ago
  8. Christians4 Group Title
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    sec

    • one year ago
  9. Christians4 Group Title
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    I ended up getting (sinx+cosx) (1/cosxsinx) for my left side

    • one year ago
  10. Christians4 Group Title
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    woo it worked

    • one year ago
  11. Christians4 Group Title
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    How do I prove identities that are like this:

    • one year ago
  12. Christians4 Group Title
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    1+tanx/1-tanx = Tan (x+pi/4)

    • one year ago
  13. myininaya Group Title
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    \[\frac{1+\tan(x)}{1-\tan(x)}=\tan(x+\frac{\pi}{4})\] I would write each side so that the function tan( ) only contains x and not both x & x+pi/4. You the sum identity for tan. If you don't know it write both sides in terms of sine and cosine. Use the sum identities for them to expand tan(x+pi/4)

    • one year ago
  14. Christians4 Group Title
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    sum identity for tan?

    • one year ago
  15. Christians4 Group Title
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    I know the cos and sin ones

    • one year ago
  16. Christians4 Group Title
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    is it just those over eachother?

    • one year ago
  17. Christians4 Group Title
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    oops im confused.

    • one year ago
  18. Christians4 Group Title
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    do u simply mean sinx/cosx?

    • one year ago
  19. phi Group Title
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    try using tan = sin/cos and see how it works out

    • one year ago
  20. Christians4 Group Title
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    alright but on the R.S what do i do with the (x +pi/4)

    • one year ago
  21. myininaya Group Title
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    \[\tan(x+\frac{\pi}{4})=\frac{\sin(x+\frac{\pi}{4})}{\cos(x+\frac{\pi}{4})}\] Use sum identity for sine and cosine.

    • one year ago
  22. phi Group Title
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    remember sin(a+b)= sin(a)cos(b) + cos(a) sin(b) and cos(a+b)= cos(a)cos(b)- sin(a)sin(b)

    • one year ago
  23. Christians4 Group Title
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    I plugged in the sum identity but i dont know what do to next I have sin and cosx's which i dont know what to do with

    • one year ago
  24. phi Group Title
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    write down what you have so far

    • one year ago
  25. Christians4 Group Title
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    sinxcospi/4 +cpsxsinpi/4 / cospi/4cosx + sinpi/4sinx

    • one year ago
  26. phi Group Title
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    pi/4 is 45º it is good to have memorized cos(45) and sin(45)

    • one year ago
  27. Christians4 Group Title
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    oh i knew that but can i convert it in the eqqn?

    • one year ago
  28. Christians4 Group Title
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    so i could right 45deg instead of pi/4?

    • one year ago
  29. phi Group Title
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    btw, notice that you have the wrong sign in the denominator

    • one year ago
  30. phi Group Title
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    pi/4 and 45 mean the same thing.... it matters when using a calculator, or in certain math operations where radians are more useful... but the cos(45º) = cos(pi/4 radians)

    • one year ago
  31. phi Group Title
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    just like 1 foot is the same as 12 inches

    • one year ago
  32. Christians4 Group Title
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    alright thanks

    • one year ago
  33. Christians4 Group Title
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    I think i got it, gotta head to class now, ill ask teacher if hes free

    • one year ago
  34. Christians4 Group Title
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    Thanks for your help

    • one year ago
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