anonymous
  • anonymous
HOW TO DETERMINE g(y)=y^3+5 is a function or not ? help me for the solutions. i need explaination on it
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
plot this equation and put a vertical line on this plot if that intersect the graph on more than one point then it is not a function but if the line intersect it at onloy one point then it is a function.
anonymous
  • anonymous
okay . :) is many to one is funtion? or one to many is function?
anonymous
  • anonymous
i didnt get you

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
okay .. one to one relation is function right? but how about many to one relation, many to many relation and and one to many relation? is that function also?
anonymous
  • anonymous
one to one relation is function many to one is a function many to many is a function one to many is not a function
anonymous
  • anonymous
ohhh. okay .. TQ
anonymous
  • anonymous
welcome
anonymous
  • anonymous
are you engineering student? do you study mechanics before this?
sirm3d
  • sirm3d
many to many is not a function
anonymous
  • anonymous
really? thank you @sirm3d

Looking for something else?

Not the answer you are looking for? Search for more explanations.