A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
prime_count = 1
start_number = 2
number_to_check = 2
while prime_count <= 1000:
result = number_to_check % start_number
if result > 0:
start_number +=1
elif result == 0:
if start_number == number_to_check:
print(number_to_check)
number_to_check +=1
prime_count +=1
start_number =2
else:
number_to_check +=1
start_number = 2
how can i modify this code to end at 1000?
anonymous
 3 years ago
prime_count = 1 start_number = 2 number_to_check = 2 while prime_count <= 1000: result = number_to_check % start_number if result > 0: start_number +=1 elif result == 0: if start_number == number_to_check: print(number_to_check) number_to_check +=1 prime_count +=1 start_number =2 else: number_to_check +=1 start_number = 2 how can i modify this code to end at 1000?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ur first control statement must be a for loop instead of while loop for (int i=1;i<=1000;i++)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You don't necessarily need to make it a forloop.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hi! I tried this code. It worked well. It stopped at 1000th prime number which is 7919.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.