Here's the question you clicked on:
DamnImBad
A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction
hint: "to the horizontal" means |dw:1352215889655:dw| so, if you want to find the x component, use cos theta
^then, multiply the force by that value
in summary, \[\huge F_x = F\cos \theta\]