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DamnImBad

  • 3 years ago

A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction

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  1. lgbasallote
    • 3 years ago
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    hint: "to the horizontal" means |dw:1352215889655:dw| so, if you want to find the x component, use cos theta

  2. lgbasallote
    • 3 years ago
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    ^then, multiply the force by that value

  3. lgbasallote
    • 3 years ago
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    in summary, \[\huge F_x = F\cos \theta\]

  4. lgbasallote
    • 3 years ago
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    in this case

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