Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sabika13

  • 3 years ago

How do I prove this by using trig identities: (2sin^2x-1)/(sinxcosx)/=tanx-cotx

  • This Question is Closed
  1. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    \[2 \sin^2 x-1= 2\sin^2x-(\sin^2x+\cos^2x)= \sin^2x-\cos^2x \]

  2. sabika13
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how does that equal to sin^2x-cos^2x

  3. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    sin^2 x + cos^2x=1

  4. sabika13
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sin^2x-cos^2x/sin^2xcosx..now what do i do

  5. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    \[\frac{ \sin^2 }{ \sin x *\cos x }- \frac{ \cos^2 x }{ sinx * \cos x }= tanx - \cot x\] clear?

  6. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    @sabika13 hope that helps you

  7. sabika13
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how doss sin^2/sinxcosx=tanx?

  8. sabika13
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    does

  9. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    |dw:1352223957740:dw| how about now?

  10. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    still confused?

  11. ghazi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 5

    |dw:1352224079572:dw|

  12. sabika13
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhhhh thank you so much, i wrote my denominator wrong, thats why i was confused

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy