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sabika13 Group Title

How do I prove this by using trig identities: (2sin^2x-1)/(sinxcosx)/=tanx-cotx

  • one year ago
  • one year ago

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  1. ghazi Group Title
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    \[2 \sin^2 x-1= 2\sin^2x-(\sin^2x+\cos^2x)= \sin^2x-\cos^2x \]

    • one year ago
  2. sabika13 Group Title
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    how does that equal to sin^2x-cos^2x

    • one year ago
  3. ghazi Group Title
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    sin^2 x + cos^2x=1

    • one year ago
  4. sabika13 Group Title
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    sin^2x-cos^2x/sin^2xcosx..now what do i do

    • one year ago
  5. ghazi Group Title
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    \[\frac{ \sin^2 }{ \sin x *\cos x }- \frac{ \cos^2 x }{ sinx * \cos x }= tanx - \cot x\] clear?

    • one year ago
  6. ghazi Group Title
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    @sabika13 hope that helps you

    • one year ago
  7. sabika13 Group Title
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    how doss sin^2/sinxcosx=tanx?

    • one year ago
  8. sabika13 Group Title
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    does

    • one year ago
  9. ghazi Group Title
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    |dw:1352223957740:dw| how about now?

    • one year ago
  10. ghazi Group Title
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    still confused?

    • one year ago
  11. ghazi Group Title
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    |dw:1352224079572:dw|

    • one year ago
  12. sabika13 Group Title
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    ohhhhh thank you so much, i wrote my denominator wrong, thats why i was confused

    • one year ago
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