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d. At some later time, the dog rolls off the side of the sled. The child continues to pull with the same force. On the axes below, sketch a graph of speed, v, versus time, t, for the sled. Include both the sled's travel with and without the dog on the sled. Clearly indicate with the symbol tr the time at which the dog rolls off.
can u do me a favor can u draw the diagram
what part u r struck
ok so (a) FN=mg-Fsin 20
i am sorry i am weak at graphs :-(
thanks for trying though
It is only in part d that you need help?
Ok, you know the aceleration before the dog jumps out, so you can draw the graph of v until that moment by using the aceleration as the slope of the line because it is the rate of change of the velocity. Do you understand it so far?
Im unsure about the acceleration. I got 0.07 m/s. Is that right?
Just to be sure, what number are you considering for g?
10 or 9.8?
I'll be back in a few minutes but I got 0.43 with 9.8
ok. I got 1.64 m/s now
So, I had a go at this, I get a) 177.4N b) 0.63 m/s/s c) 362J As for d) - the question says to sketch, so you do not need values. You just need to realise that with less mass but the same force, the acceleration will be greater, so the slope must get steeper: |dw:1352244868726:dw|