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alexyn

  • 2 years ago

A child pulls a 15-kg sled containing a 5.0-kg dog along a straight path on a horizontal surface. He exerts a force of 55 N on the sled at an angle of 20° above the horizontal, as shown in the figure above. The coefficient of friction between the sled and the surface is 0.22. a. Calculate the normal force of the surface on the system. b. Calculate the acceleration of the system. c. Calculate the work done by the child's pulling force as the system moves a distance of 7.0 m

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  1. alexyn
    • 2 years ago
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    d. At some later time, the dog rolls off the side of the sled. The child continues to pull with the same force. On the axes below, sketch a graph of speed, v, versus time, t, for the sled. Include both the sled's travel with and without the dog on the sled. Clearly indicate with the symbol tr the time at which the dog rolls off.

  2. ksaimouli
    • 2 years ago
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    can u do me a favor can u draw the diagram

  3. alexyn
    • 2 years ago
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    sure

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  4. ksaimouli
    • 2 years ago
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    what part u r struck

  5. ksaimouli
    • 2 years ago
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    ok so (a) FN=mg-Fsin 20

  6. alexyn
    • 2 years ago
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    Part D

  7. ksaimouli
    • 2 years ago
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    i am sorry i am weak at graphs :-(

  8. ksaimouli
    • 2 years ago
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    @ivanmlerner can u help her please

  9. alexyn
    • 2 years ago
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    thanks for trying though

  10. ivanmlerner
    • 2 years ago
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    It is only in part d that you need help?

  11. alexyn
    • 2 years ago
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    yes. please

  12. ivanmlerner
    • 2 years ago
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    Ok, you know the aceleration before the dog jumps out, so you can draw the graph of v until that moment by using the aceleration as the slope of the line because it is the rate of change of the velocity. Do you understand it so far?

  13. alexyn
    • 2 years ago
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    Yes.

  14. alexyn
    • 2 years ago
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    Im unsure about the acceleration. I got 0.07 m/s. Is that right?

  15. ivanmlerner
    • 2 years ago
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    Just to be sure, what number are you considering for g?

  16. ivanmlerner
    • 2 years ago
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    10 or 9.8?

  17. ivanmlerner
    • 2 years ago
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    I'll be back in a few minutes but I got 0.43 with 9.8

  18. alexyn
    • 2 years ago
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    -10

  19. alexyn
    • 2 years ago
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    ok. I got 1.64 m/s now

  20. furnessj
    • 2 years ago
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    So, I had a go at this, I get a) 177.4N b) 0.63 m/s/s c) 362J As for d) - the question says to sketch, so you do not need values. You just need to realise that with less mass but the same force, the acceleration will be greater, so the slope must get steeper: |dw:1352244868726:dw|

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