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the surface area of a cylinder is increasing by 2 pi square inches per hour and the height is decreasing by 0.1 inches per hour when the radius is 16 inches and the height is 7 inches. how fast is the radius of the cylinder changing?
 one year ago
 one year ago
the surface area of a cylinder is increasing by 2 pi square inches per hour and the height is decreasing by 0.1 inches per hour when the radius is 16 inches and the height is 7 inches. how fast is the radius of the cylinder changing?
 one year ago
 one year ago

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MisterX777Best ResponseYou've already chosen the best response.0
Just try using the chain rule, keeping in mind that Area = f(Height, Radius). In this case you know dA/dt and dH/dt at some particular moment. So, express dR/dt in terms of the stuff you know. The key word is  chain rule for partial derivatives.
 one year ago

MisterX777Best ResponseYou've already chosen the best response.0
If you'll have problems with that I can try to solve it for you, but I'll do it only after you demonstrate that you tried it on your own.
 one year ago

MisterX777Best ResponseYou've already chosen the best response.0
If I got everything right, the answer should be approximately 0.046 inches/hour.
 one year ago

StaceyBest ResponseYou've already chosen the best response.0
Write the equation/formula for the surface area. Take the derivative with respect to time, and do the substitutions so that you can solve for dr/dt.
 one year ago

ssaiph2Best ResponseYou've already chosen the best response.0
I got .07"/hr. Is the cylinder a solid?
 one year ago
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