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jaydemarie4 Group Title

What are the real or imaginary solutions of the polynomial equation?

  • 2 years ago
  • 2 years ago

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  1. rahul91 Group Title
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    put x^4=t^2 and try to solve

    • 2 years ago
  2. jaydemarie4 Group Title
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    i still don't understand..

    • 2 years ago
  3. rahul91 Group Title
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    substitute x^4 = t^2 you get t^2 - 41t + 400 = 0 can u solve this quadratic equation

    • 2 years ago
  4. jaydemarie4 Group Title
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    i can try i just dont understand algebra at all

    • 2 years ago
  5. rahul91 Group Title
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    just solve for t then put x^2 = t. u get x. u got it ? don't worry keep on practising and you will start loving the subject

    • 2 years ago
  6. zordoloom Group Title
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    BTW, there are 4 solutions and all of them are real. No imaginary zeros

    • 2 years ago
  7. jaydemarie4 Group Title
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    thanks you guys i will try to figure it out!

    • 2 years ago
  8. satellite73 Group Title
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    try factoring \[t^2-41t+400=0\] it actually factors

    • 2 years ago
  9. satellite73 Group Title
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    and a hint is that the two numbers whose product is 400 are both perfect squares

    • 2 years ago
  10. jaydemarie4 Group Title
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    thank you very much for your help!

    • 2 years ago
  11. satellite73 Group Title
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    did you get \((t-16)(t-25)=0\)? if so then you go to \(x^2-16=0,x^2-25=0\) and solve both of those for \(x\)

    • 2 years ago
  12. jaydemarie4 Group Title
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    oh alrighty. thanks :)

    • 2 years ago
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