anonymous
  • anonymous
What are the real or imaginary solutions of the polynomial equation?
Algebra
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anonymous
  • anonymous
What are the real or imaginary solutions of the polynomial equation?
Algebra
chestercat
  • chestercat
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anonymous
  • anonymous
put x^4=t^2 and try to solve
anonymous
  • anonymous
i still don't understand..
anonymous
  • anonymous
substitute x^4 = t^2 you get t^2 - 41t + 400 = 0 can u solve this quadratic equation

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anonymous
  • anonymous
i can try i just dont understand algebra at all
anonymous
  • anonymous
just solve for t then put x^2 = t. u get x. u got it ? don't worry keep on practising and you will start loving the subject
anonymous
  • anonymous
BTW, there are 4 solutions and all of them are real. No imaginary zeros
anonymous
  • anonymous
thanks you guys i will try to figure it out!
anonymous
  • anonymous
try factoring \[t^2-41t+400=0\] it actually factors
anonymous
  • anonymous
and a hint is that the two numbers whose product is 400 are both perfect squares
anonymous
  • anonymous
thank you very much for your help!
anonymous
  • anonymous
did you get \((t-16)(t-25)=0\)? if so then you go to \(x^2-16=0,x^2-25=0\) and solve both of those for \(x\)
anonymous
  • anonymous
oh alrighty. thanks :)

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