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jaydemarie4
What are the real or imaginary solutions of the polynomial equation?
put x^4=t^2 and try to solve
i still don't understand..
substitute x^4 = t^2 you get t^2 - 41t + 400 = 0 can u solve this quadratic equation
i can try i just dont understand algebra at all
just solve for t then put x^2 = t. u get x. u got it ? don't worry keep on practising and you will start loving the subject
BTW, there are 4 solutions and all of them are real. No imaginary zeros
thanks you guys i will try to figure it out!
try factoring \[t^2-41t+400=0\] it actually factors
and a hint is that the two numbers whose product is 400 are both perfect squares
thank you very much for your help!
did you get \((t-16)(t-25)=0\)? if so then you go to \(x^2-16=0,x^2-25=0\) and solve both of those for \(x\)
oh alrighty. thanks :)