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## jaydemarie4 3 years ago What are the real or imaginary solutions of the polynomial equation?

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1. rahul91

put x^4=t^2 and try to solve

2. jaydemarie4

i still don't understand..

3. rahul91

substitute x^4 = t^2 you get t^2 - 41t + 400 = 0 can u solve this quadratic equation

4. jaydemarie4

i can try i just dont understand algebra at all

5. rahul91

just solve for t then put x^2 = t. u get x. u got it ? don't worry keep on practising and you will start loving the subject

6. zordoloom

BTW, there are 4 solutions and all of them are real. No imaginary zeros

7. jaydemarie4

thanks you guys i will try to figure it out!

8. satellite73

try factoring \[t^2-41t+400=0\] it actually factors

9. satellite73

and a hint is that the two numbers whose product is 400 are both perfect squares

10. jaydemarie4

thank you very much for your help!

11. satellite73

did you get \((t-16)(t-25)=0\)? if so then you go to \(x^2-16=0,x^2-25=0\) and solve both of those for \(x\)

12. jaydemarie4

oh alrighty. thanks :)

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