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AGummiBear55

  • 3 years ago

Please help! I'm stuck on this question: Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3).

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  1. Sufiyancs
    • 3 years ago
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    easy man,, see 1st we know that its gradient is 3/2 as its perpendicular to the line y = 3/2x + 4 now we have to find y-intercept 3=(3/2)*-6 + y-intercept 3+9=y-intercept y-intercept= 12 There equation of line will be y=3/2x + 12

  2. thinker1
    • 3 years ago
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    |dw:1352232339491:dw|

  3. AGummiBear55
    • 3 years ago
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    Is the answer y=3/2x+3.... ?

  4. Sufiyancs
    • 3 years ago
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    no it is y=3/2x + 12

  5. AGummiBear55
    • 3 years ago
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    It can't be; I only have these options: y = 3 over 2x − 1 y = 3 over 2x + 3 y = −2 over 3x − 1 y = −2 over 3x + 3

  6. thinker1
    • 3 years ago
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    |dw:1352232969879:dw|

  7. AGummiBear55
    • 3 years ago
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    Thank you guys both for your help!! :D

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