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AGummiBear55 Group Title

Please help! I'm stuck on this question: Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3).

  • one year ago
  • one year ago

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  1. Sufiyancs Group Title
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    easy man,, see 1st we know that its gradient is 3/2 as its perpendicular to the line y = 3/2x + 4 now we have to find y-intercept 3=(3/2)*-6 + y-intercept 3+9=y-intercept y-intercept= 12 There equation of line will be y=3/2x + 12

    • one year ago
  2. thinker1 Group Title
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    |dw:1352232339491:dw|

    • one year ago
  3. AGummiBear55 Group Title
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    Is the answer y=3/2x+3.... ?

    • one year ago
  4. Sufiyancs Group Title
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    no it is y=3/2x + 12

    • one year ago
  5. AGummiBear55 Group Title
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    It can't be; I only have these options: y = 3 over 2x − 1 y = 3 over 2x + 3 y = −2 over 3x − 1 y = −2 over 3x + 3

    • one year ago
  6. thinker1 Group Title
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    |dw:1352232969879:dw|

    • one year ago
  7. AGummiBear55 Group Title
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    Thank you guys both for your help!! :D

    • one year ago
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