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AGummiBear55
Please help! I'm stuck on this question: Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3).
easy man,, see 1st we know that its gradient is 3/2 as its perpendicular to the line y = 3/2x + 4 now we have to find y-intercept 3=(3/2)*-6 + y-intercept 3+9=y-intercept y-intercept= 12 There equation of line will be y=3/2x + 12
Is the answer y=3/2x+3.... ?
It can't be; I only have these options: y = 3 over 2x − 1 y = 3 over 2x + 3 y = −2 over 3x − 1 y = −2 over 3x + 3
Thank you guys both for your help!! :D