anonymous
  • anonymous
Help Help Help!!!!!! 4. Use set notation to identify the shaded region. (Note: The universe is not shaded) ******Attachment Below********
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
AccessDenied
  • AccessDenied
So, what sets are being shaded here? (For a moment, I'm only looking at which ones have ANY shading. We'll deal with parts in a second.)
anonymous
  • anonymous
Well A and part of C are shaded.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

AccessDenied
  • AccessDenied
Alright. So, we're going to have A combined with some part of C. It appears here that the only part of C that is missing from the shading is the part where it intersects with B. So, if we remove B from C by subtraction, C - B, then we now are representing only the part of C not in B. We then just add in all of A to this set: We originally removed a bit of the shaded part, but here we actually add it back in. A u (C - B) Would that make sense?
AccessDenied
  • AccessDenied
* I think some classes use a slanted mark "A \ B" for subtraction rather than a minus sign "A - B", so you may use whichever you are familiar with.
anonymous
  • anonymous
sorta my understanding of set notation is not all there. lol it really confusing My teacher hasnt showed us anything with the / mark or -. we have just been using U and and upside down U and also '
AccessDenied
  • AccessDenied
Hmm... not sure how to define that region without a subtraction. One thing to note about sets is that they don't accumulate unless you add unique elements to them. If you add in the same elements as that are in the set, they would just disappear since we already have that element. U is like set addition. A U B takes the elements of A together with the elements of B. When they share elements, those elements don't repeat in the union. n / the hill thing is like finding what two sets have in common. A n B gives you the elements in both A and B. I imagine it like putting A and B on top of each other where they have the same elements and then chopping off the parts that are falling off. :P The set subtraction '-' or '\' is like taking all the parts of one set out of another. A - B means, 'take A and remove everything it shares with B. I hope maybe that helps. Unless I'm just repeating stuff you knew. :P
AccessDenied
  • AccessDenied
* The complement thing A' is sort of like U \ A, taking your universal set and then excluding A. Literally, 'everything not A'
anonymous
  • anonymous
ok that helps some. lol i just feel really dumb when it comes to this kind of stuff.
AccessDenied
  • AccessDenied
Hmm, did you only begin stuff with sets recently? I think people tend to struggle with it at first since it's like a whole new system of rules with weird 'set' things rather than numbers. :P
anonymous
  • anonymous
Yes I'm in a freshman college pre-algebra course. This is the last problem I have on a math project due tomorrow.
AccessDenied
  • AccessDenied
Ah, okay. Cool. :) Well, I am not able to think of another way of writing it other than A u (C - B) or something crazier involving subtractions. I think that is the best way of writing it.
anonymous
  • anonymous
that might be correct let me check over my note really quick and ill get back to you. thanks
AccessDenied
  • AccessDenied
You're welcome. :)
anonymous
  • anonymous
See if this helps. I'm just retarded and can't learn anything from this but this looks just like what were learning. http://www.math.hawaii.edu/~williamdemeo/Math371-Summer2011/SetOperationsAndVenDiagrams.pdf
anonymous
  • anonymous
scroll to the bottom of that page.
AccessDenied
  • AccessDenied
Hmm... It looks like \(A \cup B^c\) contains the shaded region including the stuff outside our set, so we could intersect it with \( A \cup C \) to remove the excess outside the set: \((A \cup B^c) \ \cap (A \cup C)\)
AccessDenied
  • AccessDenied
The \(A \cup B^c\) is shown on the second-to-last slide.
anonymous
  • anonymous
yeah i see that and that makes sense. so is that the answer?
anonymous
  • anonymous
this is not math! lol i hate this kind of stuff
AccessDenied
  • AccessDenied
You could probably pull the A out by reverse distribution of the union over intersections. \( M \cup (N \cap P) = (M \cup N) \cap (M \cup P)\) \( A \cup (B^c \cap C) = (A \cup B^c) \cap (A \cup C) \) That'd look a little better I think. In fact, it kind of looks like A u (C - B) like originally. I guess A u (C n B') is the same thing as that subtraction. :P
anonymous
  • anonymous
yeah i guess it must be the same thing, who knows though. i guess ill find out when i turn it in tomorrow. lol
AccessDenied
  • AccessDenied
I'm thinking about it... |dw:1352244687932:dw| Yeah, it seems to work. :D Set notation is so fun sometimes. lol
anonymous
  • anonymous
so is it A ∪ (C ∩ B')?
AccessDenied
  • AccessDenied
Yep. :)
anonymous
  • anonymous
thanks so much!!!!!!! you have been so much help!!!!!!!!!!!!!
AccessDenied
  • AccessDenied
You're welcome! I learned some things myself as well. I never knew about that complement trick instead of subtraction of sets. ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.