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Can someone show me how I would solve this using the Quadratic Formula? 2x^2 – 16x + 32 = 0
 one year ago
 one year ago
Can someone show me how I would solve this using the Quadratic Formula? 2x^2 – 16x + 32 = 0
 one year ago
 one year ago

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haleylou56Best ResponseYou've already chosen the best response.0
do you know the quadratic form?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 one year ago

xKingxBest ResponseYou've already chosen the best response.0
The + part always confuses me. Could you demonstrate how I'd substitute an equation like this into the form?
 one year ago

AccessDeniedBest ResponseYou've already chosen the best response.1
\[ x = \frac{b \pm \sqrt{b^24ac}}{2a} \text{ means:} \\ \quad x_1 = \frac{b + \sqrt{b^2  4ac}}{2a} \text{, and} \\ \quad x_2 = \frac{b  \sqrt{b^2  4ac}}{2a} \text{ are the two solutions} \] Basically, its a more compact way of writing both solutions. The typical method is to substitute your values, simplify your sqrt(b^2  4ac) and b, and then deal with splitting the \(\pm\) into two solutions + and .
 one year ago

pkjha3105Best ResponseYou've already chosen the best response.1
2x^28x8x+32=0 2x(x4)8(x4)=0 (2x8)(x4)=0 x=4,2
 one year ago

xKingxBest ResponseYou've already chosen the best response.0
Can I ask why you wrote it as 2x^28x8x+32=0
 one year ago

xKingxBest ResponseYou've already chosen the best response.0
its supposed to be b+4ac?
 one year ago
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