anonymous
  • anonymous
Can someone show me how I would solve this using the Quadratic Formula? 2x^2 – 16x + 32 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
do you know the quadratic form?
anonymous
  • anonymous
I think x=4
hartnn
  • hartnn
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
The +- part always confuses me. Could you demonstrate how I'd substitute an equation like this into the form?
AccessDenied
  • AccessDenied
\[ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \text{ means:} \\ \quad x_1 = \frac{-b + \sqrt{b^2 - 4ac}}{2a} \text{, and} \\ \quad x_2 = \frac{-b - \sqrt{b^2 - 4ac}}{2a} \text{ are the two solutions} \] Basically, its a more compact way of writing both solutions. The typical method is to substitute your values, simplify your sqrt(b^2 - 4ac) and -b, and then deal with splitting the \(\pm\) into two solutions + and -.
anonymous
  • anonymous
2x^2-8x-8x+32=0 2x(x-4)-8(x-4)=0 (2x-8)(x-4)=0 x=4,2
anonymous
  • anonymous
Can I ask why you wrote it as 2x^2-8x-8x+32=0
anonymous
  • anonymous
its supposed to be b+-4ac?

Looking for something else?

Not the answer you are looking for? Search for more explanations.