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 2 years ago
Hello! I just completed problem 3 on problem set 2. Can you guys look at my code to see if any areas to improvement? or your code to compare?
n=1;Diophantine=();check=0
while (n<70):
a=0;b=0;c=0;ans=()
while (6*a+9*b+20*c<n):
for a in range(0,100):
for b in range(0,100):
for c in range(0,100):
if 6*a+9*b+20*c == n:
ans=ans+(n,)
if len(ans)==0:
Diophantine=Diophantine+(n,)
check=0
else:check+=1
if check==6:
print Diophantine[1]
n+=1
 2 years ago
Hello! I just completed problem 3 on problem set 2. Can you guys look at my code to see if any areas to improvement? or your code to compare? n=1;Diophantine=();check=0 while (n<70): a=0;b=0;c=0;ans=() while (6*a+9*b+20*c<n): for a in range(0,100): for b in range(0,100): for c in range(0,100): if 6*a+9*b+20*c == n: ans=ans+(n,) if len(ans)==0: Diophantine=Diophantine+(n,) check=0 else:check+=1 if check==6: print Diophantine[1] n+=1

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bwCA
 2 years ago
Best ResponseYou've already chosen the best response.0please use a code pasting site:  http://dpaste.com  http://pastebin.com  http://www.repl.it/  http://pastie.org  http://codepad.org  http://ideone.com paste your code there and post the link here. select Python syntax highlighting when u paste.

LoveMathFermat
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you bwCA! here is the link: http://dpaste.com/826170/

bwCA
 2 years ago
Best ResponseYou've already chosen the best response.0i limited my for loop ranges to say n / 6 + 1 or 20 / 6 + 1. and added break statements after each for statement to break if the equation evaluated to > n

snark
 2 years ago
Best ResponseYou've already chosen the best response.1again, it's cool... might as well allow user to enter constants, and print entire solution you can see how much the break statements speed it up: try commenting them out http://dpaste.com/826177/ of course, if you allow negative constants 5a + 6b c = 17 the breaks will miss alot.

LoveMathFermat
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you !!! Guys! I really appreciate your help!
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