This is the worksheet:
https://docs.google.com/open?id=0BwF7ycixAkNZRFVEbG4xc1A5ajg
And PICTURES 1 and 4 here
https://docs.google.com/open?id=0BwF7ycixAkNZX0lvQlIyWWdxamM
Are the rectangular and triangular prisms.
I have to go now, but if you will drop off your helpful replies, I will give you a medal the minute I log back in in the morning. Please,guys, I really need help.

- anonymous

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

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- anonymous

- anonymous

- anonymous

see the first link first,

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## More answers

- anonymous

and i have to go, but if u help me ull get a medal tomorrow morning

- anonymous

Do you know how to find the area of a right triangle?

- anonymous

um,no,let me see

- anonymous

1/2 times area of rectangle it says

- anonymous

1/2lw

- anonymous

Yep. Now do you know how to find the area of a circle? Area of a rectangle?

- anonymous

area of a circle ispi r 2

- anonymous

rectangle, bh

- anonymous

Okay since you know these formulas, these questions you're doing are pretty easy.

- anonymous

Take 3. on your white sheet.

- anonymous

You have a triangle on top and a triangle on bottom, both with the same area and same angles.

- anonymous

brine, i am talking about the nets activity

- anonymous

Okay well for that triangle, you have to split it up in to 2 right triangles. The left right triangle has a height of 0.5 and a hypotenuse of 1. To find the length of that right triangle, just use the pythagorean theorem where c= the hypotenuse.

- anonymous

Next activity?

- anonymous

See the worksheet and the photos (blue and yellow) on the other link? thats what i need. the taks worksheet i did with the help of ari

- AriPotta

@etemplin, please help her

- anonymous

he wont. but okay, thanks,296

- AriPotta

why won't he?

- anonymous

Becausr. He says he is not good at math

- anonymous

Anyone you know howp can help me, id appreciate if you tagged.
i need this by tomorrow morning.

- AriPotta

- anonymous

I have to go. But please leave your replies and i will give the one who really helps me a medsl tomorrow.

- anonymous

medal*

- anonymous

4 for you on the 3rd page. You have 8 right triangles with a height of 6 and a width of 5/2 = 2.5. Since you have 8 of them, you can take the area of one of those right triangles and then multiply that by 8. (1/2)(6)(2.5)(8) = 60 in^2
Now we need to find the area of the square in the middle. (5)(5) = 25 in^2
Take those two values we found and add them together. 60 in^2 + 25 in^2 = 85 in^2

- anonymous

For some reason the beginning of that message got cut off but you get the idea.

- anonymous

I don't understand your question for the yellow and blue sheet.

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