## TenaciousT 2 years ago could someone help me to find the sum of the series from zero to infinity (3^n/(5^n)n!)

If I understand your question correctly, you would like to know what is:$\sum_{n=0}^{\infty} \frac{ 3^n }{ 5^n \times n! }$ If this is the case, then, the equation can be written as: $\sum_{n=0}^{\infty} \frac{ (\frac{3}{5})^n }{n! }$ The Taylor series of e^x is: $e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}$ Comparing the two equations, the answer would be e^(3/5) = 1.8221. Hope it helps!