A community for students.
Here's the question you clicked on:
 0 viewing
HelpMe94
 2 years ago
Sin(2x)*Sin(x)=Cos(x) ..... Solve X
HelpMe94
 2 years ago
Sin(2x)*Sin(x)=Cos(x) ..... Solve X

This Question is Closed

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0Sin(2x)= 2Sin(x)Cos(x)

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0So I Got ..... (2Sin(x)Cos(x)Sin(x))Cos(x)=0

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1try factoring them (2Sin(x)Cos(x)Sin(x))Cos(x)=0

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0Cos(x) (2 Sin(x) Sin(x))1=0

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0Cos(x) (2Sin(x)Sin(x))=1

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1hm lets try this (2Sin(x)Cos(x)Sin(x)) = Cos(x) divide both sides by cos x then (2Sin(x)Sin(x)) = 1 can you continue from here?

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0@mark_o. is it possible to combine the sines?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1(2Sin(x)Sin(x)) = 1 multiplying 2[Sin(x)]^2 = 1

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0oh i didn't see that 2 was not part of sine

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1ok from here 2[Sin(x)]^2 = 1 [Sin(x)]^2 = 1/2

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0ok then Sin(x)^2 = 1Cos(2x)/2 Right?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1nope, use power of i/2 on both sides from [Sin(x)]^2 = 1/2 ([Sin(x)]^2)^1/2 = sqrt(1/2) correct? yes or no?

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0How would this make it solve so i get answers to the unit circle?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1([Sin(x)]^2)^1/2 = sqrt(1/2) \[\sin x=\sqrt{\frac{ 1 }{ 2 }}=\frac{ 1 }{ \sqrt{2} }*\frac{ \sqrt{2} }{ \sqrt{2} }=...?\]

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1yes...you are correct x=45deg =pi/4

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0although this seems not right there should be more to this.... because i thought.... Sin(2x)Sin(x)=Cos(x) Sin(2x)Sin(x)Cos(x)=0 2Sin(x)Cos(x)Sin(x)Cos(x)=0 Cos(x)(2Sin(x)Sin(x))=1 Then Maybe..... Cos(x)(2Sin(x)Sin(x))=1 Cos(x)=1 and 2Sin(x)=1 and Sin(x)=1

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0Attached is a example of this..

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0if it is then Cos(x)=1 has solutions 0 and 2pi 2Sin(x)=1 also as Sin(x)=1/2 solutions pi/6 and 5pi/6 Sin(x)=1 solution pi/2

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1yesssssss thats right 2Sin(x)Cos(x)Sin(x)Cos(x)=0 could be like Cos(x)[(2Sin(x)Sin(x))1]=0 cos x=0 and 2Sin(x)Sin(x))1=0 x= arc cos 0 x=90deg=pi/2 and for 2Sin(x)Sin(x))1]=0 2Sin(x)Sin(x))=1

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0as long as restrictions are [0,2pi)

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1yes you got it.. lol..:D

HelpMe94
 2 years ago
Best ResponseYou've already chosen the best response.0oh that makes so much more sense after the factoring and combining of sines... lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.