anonymous
  • anonymous
Determine whether Rolle's Theorem can be applied to the function on the given interval; if so, find the value(s) of c guaranteed by the theorem. (Enter your answers as a comma-separated list. If Rolle's Theorem does not apply, enter DNE) f(x) = ln(5 − sin(x)) on [0, 2π]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Do you know the conditions of Rolle's Theorem?
anonymous
  • anonymous
no i don't !
anonymous
  • anonymous
The function has to be continuous and differentiable and f(a)=f(b)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I guess I can join in?
anonymous
  • anonymous
yeah i do but i tried and didn't get the right answer
anonymous
  • anonymous
just answered this question earlier on line class?
anonymous
  • anonymous
Okay so you know rolle's theorem states that if you have a continuous and differentiable function on [a,b] and (a,b) then there exists a number c where f'(c) is equal to zero on that interval.
anonymous
  • anonymous
So you would differentiate and set y= 0, then solve for x.
anonymous
  • anonymous
sinc \(sin(0)=\sin(2\pi)=0\) you get \(f(0)=f(2\pi)=\ln(5)\) take the derivative, set it equal to zero and solve for \(x\)
anonymous
  • anonymous
okay ! thanks for the help and yes online class :(

Looking for something else?

Not the answer you are looking for? Search for more explanations.