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JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
This looks worse than it is... it's just a matter of getting "b" all alone on one side of the equation.
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
just like if you had 2x = 4, to solve for x, you would divide both sides by 2 to get x all alone... Here, you want to get "b" all alone... so divide by all the stuff surrounding the "b" term.
 one year ago

vortish Group TitleBest ResponseYou've already chosen the best response.1
jake is right I would rather you teach it to me and show how to get to the solution so I understand how to do it next time
 one year ago

vortish Group TitleBest ResponseYou've already chosen the best response.1
ok so it would look like d/b ac/b right
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
sorry @vortish
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
I'm not sure I followed you last comment @vortish Solve D=abc for b: Get b all alone... what do you need to divide the right side by to get "b" all alone?
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
You divide both sides by the stuff next to the "b", right? Divide both sides by "ac". Do you follow?
 one year ago

vortish Group TitleBest ResponseYou've already chosen the best response.1
i think so so you are saying that it would db/ac b/ac and the bs would cancel each other out to leave us with d/ac
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
yes, sorry, if that's what you said before, that's correct... I just didn't follow it. you have D on the left, and abc on the right... divide both sides by "ac" and the "ac" cancels on the right leaving "b"... and on the left, you just have D/ac It's just moving terms around... "solving for" just means getting whatever you're solving for all alone by whatever you have to do.
 one year ago

vortish Group TitleBest ResponseYou've already chosen the best response.1
k thanks jake your a good tutor
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.2
trying... just like you.
 one year ago
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