Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lovekblue
Group Title
How many local max/ min does P(x) = x^57 + 7x^11 + 3x  1000 has?
 2 years ago
 2 years ago
lovekblue Group Title
How many local max/ min does P(x) = x^57 + 7x^11 + 3x  1000 has?
 2 years ago
 2 years ago

This Question is Closed

ghazi Group TitleBest ResponseYou've already chosen the best response.4
number of roots of first differentiation decides total number of minima and maxima , after one differentiation you will get highest order of 56 so it will have 56 roots and therefore total number is 56
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
the answer is 0
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
@ghazi answer is 0
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
can you guess what could be the reason behind zero ?
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
no.. something about (0, 1000)
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
i am unable to think why it has answer zero , i don't think so , let me call my friend @mukushla buddy help
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
@eliassaab sir, help
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
hello because P(x) is a strictly increasing function since\[P'(x)=57x^{56}+77x^{10}+3>0\]
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
@lovekblue why are you laughing bro lol
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
there you go @lovekblue
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
@mukushla sorry forgot this
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
but P(x) starts from (0,1000), wouldnt it cross 0 in some time?
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
no, it would not it will tend to zero but won't cross zero
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
how do u know o_o
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
check out the definition that muku has mentioned above
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
but what he talks about is P'(x)
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
P'(x) is strictly increasing.. that doesnt help saying it wont cross 0...
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
not P'(x) but P(x) is strictly increasing (why?) and P(x) is continous ...so there are no local Max or Min but there is a one root
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
ohh right
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
dw:1352269291734:dw think of something like this
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
dont know why i suddenly related root to max/min.. i get it now thanks!
 2 years ago

lovekblue Group TitleBest ResponseYou've already chosen the best response.0
thanks both of u :)
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.4
:) special thanks to @mukushla
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.