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sabika13
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How do I solve this using trig identities: tan(pi/4 + x) +tan(pi/4  x) =2sec2x
 2 years ago
 2 years ago
sabika13 Group Title
How do I solve this using trig identities: tan(pi/4 + x) +tan(pi/4  x) =2sec2x
 2 years ago
 2 years ago

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sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i tried left side: 1+tanx+1tanx =2 :S
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
have you studied double angle identities?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
well i have the formulas for it
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
ok good tell me formula for tan(a+b) and tan (ab) remember a and b are angles.
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
tan(a+/b)=(tana+/tanb)/(1+/tanatanb)
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
good.. now try to use this formula in your question.. it would be some thing like this for tan(pi/4 +x) = [tan(pi/4) +tanx]/(1tan(pi/4)tanx)
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
and then do i conjugate?
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
yes.. basically tan(pi/4) = 1 so just start solving as pi/4 will be eliminated.. the rest would be LCM and simple algebra.
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
i think it should work.. as where 2 angles are involved we use double angle identities to make stuff easy for us.. so this should work out.
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i ended up with tanx
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
actually it was 1+tan^2x/1+tanx
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
seriously.. hmm i will solve it and will see.. i have to go right now but will be back in a while just post the working u did.. if i can do i will post back..
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
hmm i dont think so you did right.. as far as i know there should be 1tan^2x in the denominator.
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i got (1+tanx)(1tanx)in deno
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
yes.. multiplying it would give (1tan^2x)
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
okaylet me show what i did: tanpi/4 + tanx)^2/(1tanpi/4tanx)(1+tanpi/4tanx) + tanpi/4tanx/1+tanpi/4+tanx
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
(tanpi/4+tanx)^2 + (tanpi/4tanx) / (1tanpi/4tanx)(1+tanpi/4tanx)
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
and then tanpi/4 =1
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
2+tan^2xtanx / 1tan^2x
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
yes i am.. just solving for you..
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
ok well fault i found in your answer is in frist step. tanpi/4 + tanx)^2 how you got the square here?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i multiplied (tan pi/4 +tanx) to both top and bottom
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
it will become a common deno
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
ok i got easy way.. try wolfram.. http://www.wolframalpha.com/input/?i=tan%28pi%2F4+%2B+x%29+%2Btan%28pi%2F4++x%29+%3D2sec%282x%29&dataset=&equal=Submit
 2 years ago

nubeer Group TitleBest ResponseYou've already chosen the best response.0
tell me if this helps you.
 2 years ago
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