ChristaB
1/2a^2  1/4a For a=4



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lgbasallote
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substitute a with 4....where are you confused tehre?

ChristaB
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1/2(4)^2  1/4(4)
1/2 (16)  1/4(4)
16/2 4/4 ???

lgbasallote
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that depends... is the question \[\frac 12 a^2  \frac 14a\]or\[\frac 1{2a^2}  \frac 1{4a}\]

ChristaB
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its
1/2a2  1/4a

lgbasallote
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?

ChristaB
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a^2

lgbasallote
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a^2 = \(a^2\)

ChristaB
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I am working on polynomials. The question says to "Evaluate the expression"
1/2a^2  1/4a For a= 4

lgbasallote
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and i am asking you how the question looks like...

ChristaB
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How do you get your equation to look like a real exponent on here?

lgbasallote
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is the a in the denominator or not?

lgbasallote
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is it \[\huge \frac 12 a^2  \frac 14a\]
or \[\huge \frac 1{2a^2}  \frac 1{4a}\]

ChristaB
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no, it is to the side of the of the fraction

lgbasallote
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then you're right

ChristaB
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Got it.... thank you but seriously. how did you type out the equation like that on the computer

lgbasallote
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do you see that box that says \[\huge \boxed{\sum \; \rm{Equation}}\]

lgbasallote
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below the comment box

ChristaB
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yes

ChristaB
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oh.. cool.. thank you

lgbasallote
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welcome