SugarRainbow
how to simplify square root of (9*e^4)*2*(e^3)?



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lgbasallote
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multiply (9e^4) * 2 first. what do you get?

SugarRainbow
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sorry i did that wrong its like thisdw:1352271755951:dw

lgbasallote
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well that's different... take teh square root of \(\sqrt{9e^4}\) i assume you know how to?

SugarRainbow
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you get 3e^2?

lgbasallote
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yes now multiply that to 2

SugarRainbow
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6e^2 or 6e^4?

lgbasallote
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6e^2

lgbasallote
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now multiply that to e^3

SugarRainbow
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6e^6?

lgbasallote
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no

lgbasallote
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remember rules of exponents.. \[\huge x^a \times x^b \implies x^{a + b}\]

SugarRainbow
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oh so 6e^2+3 so 6e^1?

lgbasallote
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if you have negative exponent that just becomes \[\huge x^a \times x^{b} \implies x^{a + (b)} \implies x^{a  b}\]

lgbasallote
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yes 6e^1

lgbasallote
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now...recall your rules of exponents again.. \[\huge x^{m} \implies \frac 1 {x^m}\]

SugarRainbow
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so 6e?

lgbasallote
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no. look at my comment very carefully

lgbasallote
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i didn't say \[\huge x^{m} \implies x^m\]

SugarRainbow
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so 6(1/e^1)?

lgbasallote
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yes. simplify it more

SugarRainbow
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can i multiply 6 by that? so like 6/e^1?

lgbasallote
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yes. simplify it more

SugarRainbow
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IDK how unless it's e^1/6

lgbasallote
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no

lgbasallote
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6/e^1 was already right.. you just have tp simplify it more into 6/e...e^1 = e remember?

SugarRainbow
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so 6/e?

lgbasallote
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yes

SugarRainbow
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is that it?

lgbasallote
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yes

SugarRainbow
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okay thank you goodnight :)

lgbasallote
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unless you think you can simplify it further