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how to simplify square root of (9*e^4)*2*(e^-3)?

Mathematics
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multiply (9e^4) * 2 first. what do you get?
sorry i did that wrong its like this|dw:1352271755951:dw|
well that's different... take teh square root of \(\sqrt{9e^4}\) i assume you know how to?

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Other answers:

you get 3e^2?
yes now multiply that to 2
6e^2 or 6e^4?
6e^2
now multiply that to e^-3
6e^-6?
no
remember rules of exponents.. \[\huge x^a \times x^b \implies x^{a + b}\]
oh so 6e^2+-3 so 6e^-1?
if you have negative exponent that just becomes \[\huge x^a \times x^{-b} \implies x^{a + (-b)} \implies x^{a - b}\]
yes 6e^-1
now...recall your rules of exponents again.. \[\huge x^{-m} \implies \frac 1 {x^m}\]
so 6e?
no. look at my comment very carefully
i didn't say \[\huge x^{-m} \implies x^m\]
so 6(1/e^1)?
yes. simplify it more
can i multiply 6 by that? so like 6/e^1?
yes. simplify it more
IDK how unless it's e^-1/6
no
6/e^1 was already right.. you just have tp simplify it more into 6/e...e^1 = e remember?
so 6/e?
yes
is that it?
yes
okay thank you goodnight :)
unless you think you can simplify it further

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