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SugarRainbow

how to simplify square root of (9*e^4)*2*(e^-3)?

  • one year ago
  • one year ago

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  1. lgbasallote
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    multiply (9e^4) * 2 first. what do you get?

    • one year ago
  2. SugarRainbow
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    sorry i did that wrong its like this|dw:1352271755951:dw|

    • one year ago
  3. lgbasallote
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    well that's different... take teh square root of \(\sqrt{9e^4}\) i assume you know how to?

    • one year ago
  4. SugarRainbow
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    you get 3e^2?

    • one year ago
  5. lgbasallote
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    yes now multiply that to 2

    • one year ago
  6. SugarRainbow
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    6e^2 or 6e^4?

    • one year ago
  7. lgbasallote
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    6e^2

    • one year ago
  8. lgbasallote
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    now multiply that to e^-3

    • one year ago
  9. SugarRainbow
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    6e^-6?

    • one year ago
  10. lgbasallote
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    no

    • one year ago
  11. lgbasallote
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    remember rules of exponents.. \[\huge x^a \times x^b \implies x^{a + b}\]

    • one year ago
  12. SugarRainbow
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    oh so 6e^2+-3 so 6e^-1?

    • one year ago
  13. lgbasallote
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    if you have negative exponent that just becomes \[\huge x^a \times x^{-b} \implies x^{a + (-b)} \implies x^{a - b}\]

    • one year ago
  14. lgbasallote
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    yes 6e^-1

    • one year ago
  15. lgbasallote
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    now...recall your rules of exponents again.. \[\huge x^{-m} \implies \frac 1 {x^m}\]

    • one year ago
  16. SugarRainbow
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    so 6e?

    • one year ago
  17. lgbasallote
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    no. look at my comment very carefully

    • one year ago
  18. lgbasallote
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    i didn't say \[\huge x^{-m} \implies x^m\]

    • one year ago
  19. SugarRainbow
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    so 6(1/e^1)?

    • one year ago
  20. lgbasallote
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    yes. simplify it more

    • one year ago
  21. SugarRainbow
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    can i multiply 6 by that? so like 6/e^1?

    • one year ago
  22. lgbasallote
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    yes. simplify it more

    • one year ago
  23. SugarRainbow
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    IDK how unless it's e^-1/6

    • one year ago
  24. lgbasallote
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    no

    • one year ago
  25. lgbasallote
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    6/e^1 was already right.. you just have tp simplify it more into 6/e...e^1 = e remember?

    • one year ago
  26. SugarRainbow
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    so 6/e?

    • one year ago
  27. lgbasallote
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    yes

    • one year ago
  28. SugarRainbow
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    is that it?

    • one year ago
  29. lgbasallote
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    yes

    • one year ago
  30. SugarRainbow
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    okay thank you goodnight :)

    • one year ago
  31. lgbasallote
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    unless you think you can simplify it further

    • one year ago
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