## SugarRainbow 2 years ago how to simplify square root of (9*e^4)*2*(e^-3)?

1. lgbasallote

multiply (9e^4) * 2 first. what do you get?

2. SugarRainbow

sorry i did that wrong its like this|dw:1352271755951:dw|

3. lgbasallote

well that's different... take teh square root of $$\sqrt{9e^4}$$ i assume you know how to?

4. SugarRainbow

you get 3e^2?

5. lgbasallote

yes now multiply that to 2

6. SugarRainbow

6e^2 or 6e^4?

7. lgbasallote

6e^2

8. lgbasallote

now multiply that to e^-3

9. SugarRainbow

6e^-6?

10. lgbasallote

no

11. lgbasallote

remember rules of exponents.. $\huge x^a \times x^b \implies x^{a + b}$

12. SugarRainbow

oh so 6e^2+-3 so 6e^-1?

13. lgbasallote

if you have negative exponent that just becomes $\huge x^a \times x^{-b} \implies x^{a + (-b)} \implies x^{a - b}$

14. lgbasallote

yes 6e^-1

15. lgbasallote

now...recall your rules of exponents again.. $\huge x^{-m} \implies \frac 1 {x^m}$

16. SugarRainbow

so 6e?

17. lgbasallote

no. look at my comment very carefully

18. lgbasallote

i didn't say $\huge x^{-m} \implies x^m$

19. SugarRainbow

so 6(1/e^1)?

20. lgbasallote

yes. simplify it more

21. SugarRainbow

can i multiply 6 by that? so like 6/e^1?

22. lgbasallote

yes. simplify it more

23. SugarRainbow

IDK how unless it's e^-1/6

24. lgbasallote

no

25. lgbasallote

6/e^1 was already right.. you just have tp simplify it more into 6/e...e^1 = e remember?

26. SugarRainbow

so 6/e?

27. lgbasallote

yes

28. SugarRainbow

is that it?

29. lgbasallote

yes

30. SugarRainbow

okay thank you goodnight :)

31. lgbasallote

unless you think you can simplify it further