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lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
multiply (9e^4) * 2 first. what do you get?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
sorry i did that wrong its like thisdw:1352271755951:dw
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
well that's different... take teh square root of \(\sqrt{9e^4}\) i assume you know how to?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
you get 3e^2?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
yes now multiply that to 2
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
6e^2 or 6e^4?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
now multiply that to e^3
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
6e^6?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
remember rules of exponents.. \[\huge x^a \times x^b \implies x^{a + b}\]
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
oh so 6e^2+3 so 6e^1?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
if you have negative exponent that just becomes \[\huge x^a \times x^{b} \implies x^{a + (b)} \implies x^{a  b}\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
yes 6e^1
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
now...recall your rules of exponents again.. \[\huge x^{m} \implies \frac 1 {x^m}\]
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
so 6e?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
no. look at my comment very carefully
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
i didn't say \[\huge x^{m} \implies x^m\]
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
so 6(1/e^1)?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
yes. simplify it more
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
can i multiply 6 by that? so like 6/e^1?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
yes. simplify it more
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
IDK how unless it's e^1/6
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
6/e^1 was already right.. you just have tp simplify it more into 6/e...e^1 = e remember?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
so 6/e?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
is that it?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.1
okay thank you goodnight :)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
unless you think you can simplify it further
 2 years ago
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