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SheldonEinstein
Group Title
A( \(z_A\) ) , B ( \(z_B\) ) , C ( \(z_C\) ) are vertices of right angled triangle, \(z_c\) being the orthocentre. A circle is described on AC as diameter. Find the point of intersection of the circle with hypotenuse.
 one year ago
 one year ago
SheldonEinstein Group Title
A( \(z_A\) ) , B ( \(z_B\) ) , C ( \(z_C\) ) are vertices of right angled triangle, \(z_c\) being the orthocentre. A circle is described on AC as diameter. Find the point of intersection of the circle with hypotenuse.
 one year ago
 one year ago

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SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
@mukushla
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
OK what can I do is just draw a diagram on the basis of the given information first... wait
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
@mukushla is not online this time..
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
dw:1352285181683:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
There it is!
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
If we draw a line from point C to the intersection point, the line will make 90 degrees and will be perpendicular to AB..
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
dw:1352334002288:dw
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
It is by the property of Semi circle..
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
And we are to find its coordinates.. And @UnkleRhaukus will solve this further... Ha ha ha...
 one year ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
Z(A), Z(B) and Z(c) are complex numbers?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
It is by the property of Semi circle! thats right! dw:1352285595958:dw
 one year ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
Without loss of generality we can assume C is the origin ..it'll simplify the problem dw:1352285727325:dw
 one year ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
if Z(A), Z(B), Z(C) are complex numbers..
 one year ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
i have made some more assumption...AC=BC
 one year ago

akash123 Group TitleBest ResponseYou've already chosen the best response.0
otherwise use (Z0)/(z00) ={ I z I / I Z0 I }e^( i pi/2)
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 and @myininaya may share their ideas ...
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
if i were to add anything, and im not sure how to read the notation in the problem; so i cant determine if the complex stuff is appropriate or not, but dw:1352297044749:dw
 one year ago
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