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inkyvoydBest ResponseYou've already chosen the best response.0
Current work:\(\huge f''(x)=\ln6(6^{x^2+3})(4\ln6*x^3+6x)\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
What am I doing wrong?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
work: for f'(x), set apply the product rule, getting u=x u'=1 v=6^(x^2+3) v'=2 ln6*x*6^(x^2+3) the result is 2ln6*x^2*6^(x^2+3)+6^(x^2+3)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
for f''(x), factor out constants, 2ln6 d/dx (x^2+6^(x^2+3))+ d/dx (6^(x^2+3))
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
Nevermind I got this right apparently.
 one year ago
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