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inkyvoyd

  • 3 years ago

find f''(x) if f(x)=x(6^(x^2+3))

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  1. inkyvoyd
    • 3 years ago
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    Current work:\(\huge f''(x)=\ln6(6^{x^2+3})(4\ln6*x^3+6x)\)

  2. inkyvoyd
    • 3 years ago
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    What am I doing wrong?

  3. inkyvoyd
    • 3 years ago
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    work: for f'(x), set apply the product rule, getting u=x u'=1 v=6^(x^2+3) v'=2 ln6*x*6^(x^2+3) the result is 2ln6*x^2*6^(x^2+3)+6^(x^2+3)

  4. inkyvoyd
    • 3 years ago
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    for f''(x), factor out constants, 2ln6 d/dx (x^2+6^(x^2+3))+ d/dx (6^(x^2+3))

  5. inkyvoyd
    • 3 years ago
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    Nevermind I got this right apparently.

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