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inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Current work:\(\huge f''(x)=\ln6(6^{x^2+3})(4\ln6*x^3+6x)\)

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0What am I doing wrong?

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0work: for f'(x), set apply the product rule, getting u=x u'=1 v=6^(x^2+3) v'=2 ln6*x*6^(x^2+3) the result is 2ln6*x^2*6^(x^2+3)+6^(x^2+3)

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0for f''(x), factor out constants, 2ln6 d/dx (x^2+6^(x^2+3))+ d/dx (6^(x^2+3))

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Nevermind I got this right apparently.
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