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i am given \[\frac{dz}{dx} = -1\] at (3,4) and\[\frac{dz}{dy} = 2\] at (3,4)

\[\frac{dx}{d \theta} = -\sqrt{5}\sin (\theta )\]

\[\frac{dy}{d \theta} = \sqrt{5}\cos( \theta )\]

put \( \theta =\arctan( 4/3) \)