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zaphod Group TitleBest ResponseYou've already chosen the best response.0
http://screencast.com/t/FGxsE787eeNs
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest @Preetha @Omniscience @amistre64 @Algebraic!
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok lets try this.. can you find the total resistance of the circuit?
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
1/4 + 1/6 + 2 = total resistance
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
as a matter of fact no.. 1/r = 1/r1+1/r2
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u show the working
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
first just try to find the resistance in parallel then add it in series one so u dont make mistake.. and ok let me
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
first just find the parallel part of resistance.. 1/r = 1/6+1/4 1/r = 5/12 agreed?
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
ok total resistance = 12/5 + 2
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
yes.. that's it.. so you have R now.. you also have V given so appply V=IR find I from here it will be your A1
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
ok wt will A2 nd A3 be?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok.. now if you know.. when a resitor in series there is a drop in voltage.. and in parallel all resistors have same voltage.
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
so find the drop on 3ohm resistor which is in series by V=IR
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i dont get that part. now the current in a1 = 2.72 amps, so the voltage is 12v?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
the volatge of whole circuit is 12V .. now you have to find the drop in voltage across just 3ohm resistor.. means a voltage is decreased at the 3 ohm resitor.. you have to find how much 3ohm took and what is remaining left.. like this .. if A=2.72 and R=3 V=2.72*3 = ?
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
oh okay...so voltage = 8.18 V, then what do i do
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok means from 12V.. 3ohm took 8.18V.. how much voltage is left.?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
ok so now 3.81 V will move on.. now the part is parallel resistors .. when resistors are in paralle they both have same voltage... so 6ohm and 4ohm resistor have same voltage. now again you can find I by V=IR
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
means both the resistors hve 3.81 V
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
because they are in parallel..
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
okay thanks...great help du knw anyother easy method of solving this
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
lol .. its pretty easy.. you just have to do more practise.. it just take 1 min for me to solve.. maybe you can ask someone else for other method.. but this is the only one i know for now.
 one year ago

furnessj Group TitleBest ResponseYou've already chosen the best response.0
i am not actually great at these, but i am worried you have some mistakes. The total resistance is 12/5 + 3 = 5.4 ohms. Then the current A1 = 2.22 A. Plus now, it is easy to split the current between the 4 and 6 ohm resistors. the 4 ohm gets (4/10) * 2.22 , the 6 gets (6/10) * 2.22. Does this help/do you agree?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.1
i am sorry.. i havent checked the calculations.. i thought he might have done right.. i was just trying to convey the concept.. and ya i think i agree.
 one year ago
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