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anonymous
 4 years ago
What is the value of current in A1, A2 and A3
anonymous
 4 years ago
What is the value of current in A1, A2 and A3

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@TuringTest @Preetha @Omniscience @amistre64 @Algebraic!

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1ok lets try this.. can you find the total resistance of the circuit?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01/4 + 1/6 + 2 = total resistance

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1as a matter of fact no.. 1/r = 1/r1+1/r2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u show the working

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1first just try to find the resistance in parallel then add it in series one so u dont make mistake.. and ok let me

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1first just find the parallel part of resistance.. 1/r = 1/6+1/4 1/r = 5/12 agreed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok total resistance = 12/5 + 2

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1yes.. that's it.. so you have R now.. you also have V given so appply V=IR find I from here it will be your A1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok wt will A2 nd A3 be?

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1ok.. now if you know.. when a resitor in series there is a drop in voltage.. and in parallel all resistors have same voltage.

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1so find the drop on 3ohm resistor which is in series by V=IR

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont get that part. now the current in a1 = 2.72 amps, so the voltage is 12v?

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1the volatge of whole circuit is 12V .. now you have to find the drop in voltage across just 3ohm resistor.. means a voltage is decreased at the 3 ohm resitor.. you have to find how much 3ohm took and what is remaining left.. like this .. if A=2.72 and R=3 V=2.72*3 = ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay...so voltage = 8.18 V, then what do i do

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1ok means from 12V.. 3ohm took 8.18V.. how much voltage is left.?

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1ok so now 3.81 V will move on.. now the part is parallel resistors .. when resistors are in paralle they both have same voltage... so 6ohm and 4ohm resistor have same voltage. now again you can find I by V=IR

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0means both the resistors hve 3.81 V

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1because they are in parallel..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay thanks...great help du knw anyother easy method of solving this

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1lol .. its pretty easy.. you just have to do more practise.. it just take 1 min for me to solve.. maybe you can ask someone else for other method.. but this is the only one i know for now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am not actually great at these, but i am worried you have some mistakes. The total resistance is 12/5 + 3 = 5.4 ohms. Then the current A1 = 2.22 A. Plus now, it is easy to split the current between the 4 and 6 ohm resistors. the 4 ohm gets (4/10) * 2.22 , the 6 gets (6/10) * 2.22. Does this help/do you agree?

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.1i am sorry.. i havent checked the calculations.. i thought he might have done right.. i was just trying to convey the concept.. and ya i think i agree.
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