I am working on exercise 2.1 on homework 2.0. We are being asked to write a function that takes parameters instead of asking for user input for our Rock, Paper, Scissors program. I created the following function but I can't capture the return value and was wondering if you could help
if x == 'rock' or x == 'scissors' or x == 'paper':
print "still trying"
and I call it this way
I want to take the results of return x and put that into a variable called player_a and I can't make it work. I feel so dense thi
MIT 6.189 A Gentle Introduction to Programming Using Python (OCW)
Stacey Warren - Expert brainly.com
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player_a = p1('rock')
But that would just print 'rock'?
yes, I did that and discovered that it does just as you said .. it prints rock regardless of how I call the function.
Well it would print 'paper' if you said:
player_a = p1('paper')
Your game of Rock Paper Scissors will need 2 arguments though. Player 1's and Player 2' choice. These 2 need to be compared and the winner decided.
def rps(player_1, player_2):
#do logic against choices here
#return the winner
winner = rps('rock', 'paper)
Something to that effect. Hope this helps somewhat.
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it must return a value either way:
if x == 'rock' or x == 'stone':
Thanks Andrew and Snark. I am going to rethink my approach based on Andrew's comments. I think the problem I am struggling with is the fact that rock, paper or scissors are strings and when I call the function, I call it as rps('rock') or rps('paper'), etc.
you can use random:
you can call it this way:
if that make sense. I hope that was helpful