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CliffSedgeBest ResponseYou've already chosen the best response.2
\(\large ln(4^s) = s \cdot ln(4)\)
 one year ago

bmelykBest ResponseYou've already chosen the best response.0
so it would be s/4 then.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
ln(4) is a constant
 one year ago

bmelykBest ResponseYou've already chosen the best response.0
yes but the derivative of ln=1/x
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
If you are finding \(\large y'=\frac{d}{ds}[ ln(4^s)]\) \(\large y'=\frac{d}{ds}[ ln(4)s] =\frac{d}{ds}[c\cdot s], \space c=ln(4)\)
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
The derivative of ln x is 1/x, but ln 4 is a constant, and the derivative of a constant is zero.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
But here you are taking the derivative of a constant times a variable.
 one year ago

bmelykBest ResponseYou've already chosen the best response.0
im confused by your explanation.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
the derivative is with respect to s what is d/ds(s) ?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
no, what is d/dx(x) ?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
s' would be if s was a function of some other variable.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
yes, so we just changed the name of s to x ...so d/ds(s)=?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
yes :) now what if we multiply by a constant that we call 'c' ? then d/ds(cs)=?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
yes now for your problem we can write ln(4^s)=s*ln4 ln4 is a constant, so d/ds(ln(4^s))=?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
Thanks for the backup, Turing!
 one year ago
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