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does y' of ln(4^s) = 1/4^s or s/4 ??

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\(\large ln(4^s) = s \cdot ln(4)\)
so it would be s/4 then.
ln(4) is a constant

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Other answers:

yes but the derivative of ln=1/x
If you are finding \(\large y'=\frac{d}{ds}[ ln(4^s)]\) \(\large y'=\frac{d}{ds}[ ln(4)s] =\frac{d}{ds}[c\cdot s], \space c=ln(4)\)
The derivative of ln x is 1/x, but ln 4 is a constant, and the derivative of a constant is zero.
But here you are taking the derivative of a constant times a variable.
what is c*s ???
im confused by your explanation.
the derivative is with respect to s what is d/ds(s) ?
umm s'?
no, what is d/dx(x) ?
s' would be if s was a function of some other variable.
yes, so we just changed the name of s to x d/ds(s)=?
=1 !
yes :) now what if we multiply by a constant that we call 'c' ? then d/ds(cs)=?
yes now for your problem we can write ln(4^s)=s*ln4 ln4 is a constant, so d/ds(ln(4^s))=?
so thats the answer?
Thanks for the backup, Turing!
No prob!

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