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anonymous
 4 years ago
does y' of ln(4^s) = 1/4^s or s/4 ??
anonymous
 4 years ago
does y' of ln(4^s) = 1/4^s or s/4 ??

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(\large ln(4^s) = s \cdot ln(4)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it would be s/4 then.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but the derivative of ln=1/x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you are finding \(\large y'=\frac{d}{ds}[ ln(4^s)]\) \(\large y'=\frac{d}{ds}[ ln(4)s] =\frac{d}{ds}[c\cdot s], \space c=ln(4)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The derivative of ln x is 1/x, but ln 4 is a constant, and the derivative of a constant is zero.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But here you are taking the derivative of a constant times a variable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im confused by your explanation.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2the derivative is with respect to s what is d/ds(s) ?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2no, what is d/dx(x) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0s' would be if s was a function of some other variable.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2yes, so we just changed the name of s to x ...so d/ds(s)=?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2yes :) now what if we multiply by a constant that we call 'c' ? then d/ds(cs)=?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2yes now for your problem we can write ln(4^s)=s*ln4 ln4 is a constant, so d/ds(ln(4^s))=?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks for the backup, Turing!
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