janet2009
log(x)+log(x+2)=2



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myininaya
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log(a)+log(b)=log(ab)

janet2009
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is there any way you can help me solve the problem?

myininaya
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Yep.
I just gave you a hint.
Use that hint on the left hand side.

janet2009
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so I tried using that formula but the answer is a huge number.

myininaya
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So you did log(x(x+2))=2 because that is what I asked you to do.

myininaya
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Then base 10 on both sides so you can undo that log on that one side.

myininaya
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\[10^{\log(x(x+2))}=10^2 \]

janet2009
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yes i did that and from there I get X^2+2x=10^2 which becomes x^2+2x100?

myininaya
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Solve for x and see if both solutions will work.