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anonymous
 3 years ago
A mass m1 = 3.5 kg rests on a frictionless table and connected by a massless string over a massless pulley to another mass m2 = 4.8 kg which hangs freely from the string. When released, the hanging mass falls a distance d = 0.71 m.
1) How much work is done by gravity on the two block system?
34 J (All of my answers are correct up to the last question, which I need help on)
2) 2) How much work is done by the normal force on m1?
0 J
3) What is the final speed of the two blocks?
2.84 m/s
4) How much work is done by tension on m1?
14.1 J
5) What is the tension in the string as the block falls?
19.9 N
7) What is the NET work done on m2?
**** This is the question I need help on. I gave the answers to the previous questions because something in there might be needed for solving this part of the problem.
anonymous
 3 years ago
A mass m1 = 3.5 kg rests on a frictionless table and connected by a massless string over a massless pulley to another mass m2 = 4.8 kg which hangs freely from the string. When released, the hanging mass falls a distance d = 0.71 m. 1) How much work is done by gravity on the two block system? 34 J (All of my answers are correct up to the last question, which I need help on) 2) 2) How much work is done by the normal force on m1? 0 J 3) What is the final speed of the two blocks? 2.84 m/s 4) How much work is done by tension on m1? 14.1 J 5) What is the tension in the string as the block falls? 19.9 N 7) What is the NET work done on m2? **** This is the question I need help on. I gave the answers to the previous questions because something in there might be needed for solving this part of the problem.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay nm, got it. Just a rounding error in the velocity calculation. 7. is (0.5)(4.8)(2.84^2) = 19.4 J
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