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sabika13
Group Title
Write an equation this is equivalent to f(x)=5sin(xpi/2)  8 using trig.function of x
 one year ago
 one year ago
sabika13 Group Title
Write an equation this is equivalent to f(x)=5sin(xpi/2)  8 using trig.function of x
 one year ago
 one year ago

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richyw Group TitleBest ResponseYou've already chosen the best response.0
ok so you have \[f(x)=5\sin\left(x\frac{\pi}{2}\right)8\] For now just focus on \[g(x)=\sin\left(x\frac{\pi}{2}\right)\] what does this do to the graph?
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
where \(x=\pi/2\), what is \[\sin\left(x\frac{\pi}{2}\right)\]also brb. just gotta hand in something quick...
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
okay.. will it be sin(xpi/2)=0??
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
i dont really understand the question itself
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
sorry open study died on me.
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
You are correct that \(g(\pi/2)=0\) You can repeat this with some other key xvalues \(x=\pi/2,\quad x=\pi ,\quad x=0 \) and find that what you get is \[\sin\left(x\frac{\pi}{2}\right)=\cos\pi\]
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
you will eventually just memorize these phase shifts, but if you ever forget on a test, you can always make a quick sketch using the method I explained. So now remember that we called \[g(x)=\sin\left(x\frac{\pi}{2}\right)=\cos x\] Going back to the original function you have \[f(x)=5\sin\left(x\frac{\pi}{2}\right)8\]\[f(x)=5g(x)8\]So the hard part is already done. The 8 is all by itself so it just shifts the up and down, and the 5 just makes the amplitude of the wave greater. All you have to do now is plug in the expression you worked out for g(x). \[f(x)=5(\cos x)8\]\[f(x)=5\cos x 8\]
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
Oops made a mistake, in the second last post. It should say : You are correct that \(g(π/2)=0\) You can repeat this with some other key xvalues \(x=π/2,\quad x=π,\quad x=0\) and find that what you get is \[\sin\left( x−\frac{\pi}{2}\right)=−\cos x\]
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
sorry i fell alseep _ .. accoriding the the cofunction identities isnt it : cosx=sin(pi/2x)? so using that you can get cosx=sin(xpi/2) (sorrydont understand)
 one year ago
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