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brandonlovesBest ResponseYou've already chosen the best response.0
I could be totally off, but I just wanted to give it a shot. I got 8/3, 3 again, I could be way wrong, but I just wanted to try it/see if I remembered. good luck you know the formula right?
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
dw:1352320744523:dw
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
dw:1352320782461:dw
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
dw:1352320879213:dw
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
or none of the above
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
dw:1352320868071:dw I think I'm right up till this point, but I think I get messed up after that.
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
the answer is the last one i believe?
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
oh, I see how you got the 40. isn't it 4(a)(c) though? I got 24 + 16 to get 8 under the radical
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
dw:1352321326332:dw
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
http://www.purplemath.com/modules/quadform.htm
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
@.UserNotFound. am i correct because
 one year ago

.UserNotFound.Best ResponseYou've already chosen the best response.0
http://answers.yahoo.com/question/index?qid=20091117132621AAECMYZ ??
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
yea, and I'm not much help haha. I tried though. I'd check out khanacademy.org or watch some youtube videos till someone with more quadform exp can help hah
 one year ago

rebecca1233Best ResponseYou've already chosen the best response.0
i just wanna know if i am correct
 one year ago

jasonxxBest ResponseYou've already chosen the best response.1
\[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }=\frac{ 4 \pm \sqrt{164*3*(2)} }{ 2*3 }= \frac{ 4 \pm \sqrt{40} }{ 6 }\] @rebecca1233
 one year ago

jasonxxBest ResponseYou've already chosen the best response.1
@rebecca1233 come on now show me , yor answer is here
 one year ago
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