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rebecca1233
Group Title
Solve by using the quadratic formula. 3x^2  4x = 2
 one year ago
 one year ago
rebecca1233 Group Title
Solve by using the quadratic formula. 3x^2  4x = 2
 one year ago
 one year ago

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rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
@jasonxx
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
I could be totally off, but I just wanted to give it a shot. I got 8/3, 3 again, I could be way wrong, but I just wanted to try it/see if I remembered. good luck you know the formula right?
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352320744523:dw
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352320782461:dw
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352320879213:dw
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
or none of the above
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
dw:1352320868071:dw I think I'm right up till this point, but I think I get messed up after that.
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
the answer is the last one i believe?
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
oh, I see how you got the 40. isn't it 4(a)(c) though? I got 24 + 16 to get 8 under the radical
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352321326332:dw
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
idk im confused
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
http://www.purplemath.com/modules/quadform.htm
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
@.UserNotFound. am i correct because
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
i need help
 one year ago

.UserNotFound. Group TitleBest ResponseYou've already chosen the best response.0
http://answers.yahoo.com/question/index?qid=20091117132621AAECMYZ ??
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
yea, and I'm not much help haha. I tried though. I'd check out khanacademy.org or watch some youtube videos till someone with more quadform exp can help hah
 one year ago

rebecca1233 Group TitleBest ResponseYou've already chosen the best response.0
i just wanna know if i am correct
 one year ago

jasonxx Group TitleBest ResponseYou've already chosen the best response.1
let me check
 one year ago

jasonxx Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }=\frac{ 4 \pm \sqrt{164*3*(2)} }{ 2*3 }= \frac{ 4 \pm \sqrt{40} }{ 6 }\] @rebecca1233
 one year ago

jasonxx Group TitleBest ResponseYou've already chosen the best response.1
@rebecca1233 come on now show me , yor answer is here
 one year ago
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