anonymous
  • anonymous
Solve by using the quadratic formula. 3x^2 - 4x = 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@jasonxx
anonymous
  • anonymous
I could be totally off, but I just wanted to give it a shot. I got 8/3, 3 again, I could be way wrong, but I just wanted to try it/see if I remembered. good luck you know the formula right?
anonymous
  • anonymous
|dw:1352320744523:dw|

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anonymous
  • anonymous
|dw:1352320782461:dw|
anonymous
  • anonymous
|dw:1352320879213:dw|
anonymous
  • anonymous
or none of the above
anonymous
  • anonymous
|dw:1352320868071:dw| I think I'm right up till this point, but I think I get messed up after that.
anonymous
  • anonymous
the answer is the last one i believe?
anonymous
  • anonymous
oh, I see how you got the 40. isn't it -4(a)(c) though? I got -24 + 16 to get -8 under the radical
anonymous
  • anonymous
|dw:1352321326332:dw|
anonymous
  • anonymous
idk im confused
anonymous
  • anonymous
http://www.purplemath.com/modules/quadform.htm
anonymous
  • anonymous
@.UserNotFound. am i correct because
anonymous
  • anonymous
i need help
anonymous
  • anonymous
http://answers.yahoo.com/question/index?qid=20091117132621AAECMYZ ??
anonymous
  • anonymous
yea, and I'm not much help haha. I tried though. I'd check out khanacademy.org or watch some youtube videos till someone with more quadform exp can help hah
anonymous
  • anonymous
i just wanna know if i am correct
anonymous
  • anonymous
let me check
anonymous
  • anonymous
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }=\frac{ 4 \pm \sqrt{16-4*3*(-2)} }{ 2*3 }= \frac{ 4 \pm \sqrt{40} }{ 6 }\] @rebecca1233
anonymous
  • anonymous
@rebecca1233 come on now show me , yor answer is here

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