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ExtremeAnon
 2 years ago
√(6x+5)= √53
ExtremeAnon
 2 years ago
√(6x+5)= √53

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ExtremeAnon
 2 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE \sqrt{6x+5} = \sqrt{53}\]

surdawi
 2 years ago
Best ResponseYou've already chosen the best response.0square both sides what do you get?

hba
 2 years ago
Best ResponseYou've already chosen the best response.0Squaring both sides Would Help :)

ExtremeAnon
 2 years ago
Best ResponseYou've already chosen the best response.0Idk, I don't know how to square a square root??

surdawi
 2 years ago
Best ResponseYou've already chosen the best response.0\[\left( \sqrt{a} \right)^2\]

surdawi
 2 years ago
Best ResponseYou've already chosen the best response.0\[\left( \sqrt{a} \right)^2=a\]

surdawi
 2 years ago
Best ResponseYou've already chosen the best response.0@ExtremeAnon you there?

hba
 2 years ago
Best ResponseYou've already chosen the best response.0\[(6x+5)^{1/2}=(53)^{1/2}\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.0\[[(6x+5)^{1/2}]^2=[(53)^{1/2}]^2\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.0@ExtremeAnon Please Participate ................

ExtremeAnon
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry i was busy. i'm back nOW1

ExtremeAnon
 2 years ago
Best ResponseYou've already chosen the best response.0i don't understand a lick of what y'all just posted... can you explain?

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.1_/(6x+5)=_/53 _/(x+5)^2=_/53^2 6x+5=53 6x=48 x=8

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.1_/= The square root of (since there is not a button for that). ^= The exponent.

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.1When you square both sides the square roots go away.

ExtremeAnon
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. Thank you so much :D

hba
 2 years ago
Best ResponseYou've already chosen the best response.0@jeans123 Please take a look at the CoC.
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