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ExtremeAnon
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\[\LARGE \sqrt{6x+5} = \sqrt{53}\]

ExtremeAnon
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Help, please?? :)

surdawi
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square both sides what do you get?

hba
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Squaring both sides Would Help :)

ExtremeAnon
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Idk, I don't know how to square a square root??

surdawi
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\[\left( \sqrt{a} \right)^2\]

surdawi
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\[\left( \sqrt{a} \right)^2=a\]

surdawi
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6x + 5 = 53

surdawi
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does that help?

surdawi
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@ExtremeAnon you there?

hba
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\[(6x+5)^{1/2}=(53)^{1/2}\]

hba
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Now Squaring both sides :)

hba
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\[[(6x+5)^{1/2}]^2=[(53)^{1/2}]^2\]

hba
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@ExtremeAnon Please Participate ................

ExtremeAnon
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Sorry i was busy. i'm back nOW1

ExtremeAnon
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i don't understand a lick of what y'all just posted... can you explain?

Jeans123
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_/(6x+5)=_/53
_/(x+5)^2=_/53^2
6x+5=53
6x=48
x=8

Jeans123
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_/= The square root of (since there is not a button for that).
^= The exponent.

Jeans123
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When you square both sides the square roots go away.

Jeans123
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Did that help at all?

ExtremeAnon
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Yes. Thank you so much :D

hba
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@jeans123 Please take a look at the CoC.