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dopek.i.d.s
 2 years ago
Best ResponseYou've already chosen the best response.06x(x+5)(5x(+5))+1=6x(x+5)

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0I figured... level 48 and 18 at helping people hmmm..:)

chloe123
 2 years ago
Best ResponseYou've already chosen the best response.0i got to 6x^2 + 55x + 126

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2umm....its completely factored but i think you mean you want it simplified...? :)

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0x^2 = x*x (x+a)^2 = (x+a)(x+a) c(x+a)= c*x + c*a

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2after that i think it can be factored :)

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0Well I know the answer it is (2x+9)(3x+14)

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2yes so lets see how to do that

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0my teacher gave that to me but I do not know how to get it.

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0So we need to simplify it, combine like terms, then refactor it

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.06(x+5)^25(x+5)+1 6(x^2+10x+25)5x25+1 6x^2+55x+126

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0This is where it gets difficult to factor.

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0_/= The square root of.

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2\[6(x+5)^25(x+5)+1\]lets simplify this: expand the \((x+5)\) and distribute the \(5\) to the parenthesis\[6(x^2+10x+25)5x25+1\]distribute the \(6\)\[6x^2+60x+1505x25+1\]combine like terms:\[6x^2+55x+126\]Now , we can factor it...i would use Quadratic equation since i find ti to be the "safest":\[{55\pm\sqrt{55^24(6)(126)}}\over2(6)\]\[{55\pm\sqrt{30253024}}\over12\]\[{55\pm\sqrt{1}}\over12\]\[{55\pm1}\over12\]\[{56\over12}~~~~or~~~~{54\over12}\]\[x={14\over3}~~~~or~~~~x={9\over2}\] so that means that its...\[(x+{14\over3})~~~and~~~(x+{9\over2})\]so to make those 'unfractioned we'll multiply by the denominators:\[\large(3x+14)(2x+9)\] tada! :D

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2@Jeans123 hope that helps! :)

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0I have been proved wrong. @yummydum that was smart to use the quadratic. He found the solutions for x so he knew what the other terms had to be. Then he got rid of the fractions by multiplying by the denominator

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0Sry just habbit of typing, didn't mean anything by it

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you both of you he and she;)

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2no harm :) ...Youre Welcome Austin! :) feel free to ask more anytime you need help (when im there of course :))

Jeans123
 2 years ago
Best ResponseYou've already chosen the best response.0In about five minutes I will:)

yummydum
 2 years ago
Best ResponseYou've already chosen the best response.2i leave pretty soon so ask now if you can :)
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