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Jeans123
Group Title
I need help!!!!!!!!!!!!!!!
Factor the expression completely,
6(x+5)^25(x+5)+1
 one year ago
 one year ago
Jeans123 Group Title
I need help!!!!!!!!!!!!!!! Factor the expression completely, 6(x+5)^25(x+5)+1
 one year ago
 one year ago

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dopek.i.d.s Group TitleBest ResponseYou've already chosen the best response.0
6x(x+5)(5x(+5))+1=6x(x+5)
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
@dopek.i.d.s is incorrect
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
I figured... level 48 and 18 at helping people hmmm..:)
 one year ago

chloe123 Group TitleBest ResponseYou've already chosen the best response.0
i got to 6x^2 + 55x + 126
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
umm....its completely factored but i think you mean you want it simplified...? :)
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
x^2 = x*x (x+a)^2 = (x+a)(x+a) c(x+a)= c*x + c*a
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
after that i think it can be factored :)
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
Well I know the answer it is (2x+9)(3x+14)
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
yes so lets see how to do that
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
my teacher gave that to me but I do not know how to get it.
 one year ago

dopek.i.d.s Group TitleBest ResponseYou've already chosen the best response.0
u guys go
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
So we need to simplify it, combine like terms, then refactor it
 one year ago

dopek.i.d.s Group TitleBest ResponseYou've already chosen the best response.0
i feel stupid now
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
6(x+5)^25(x+5)+1 6(x^2+10x+25)5x25+1 6x^2+55x+126
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
This is where it gets difficult to factor.
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
x=b+_/b^24ac/2a?
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
_/= The square root of.
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
\[6(x+5)^25(x+5)+1\]lets simplify this: expand the \((x+5)\) and distribute the \(5\) to the parenthesis\[6(x^2+10x+25)5x25+1\]distribute the \(6\)\[6x^2+60x+1505x25+1\]combine like terms:\[6x^2+55x+126\]Now , we can factor it...i would use Quadratic equation since i find ti to be the "safest":\[{55\pm\sqrt{55^24(6)(126)}}\over2(6)\]\[{55\pm\sqrt{30253024}}\over12\]\[{55\pm\sqrt{1}}\over12\]\[{55\pm1}\over12\]\[{56\over12}~~~~or~~~~{54\over12}\]\[x={14\over3}~~~~or~~~~x={9\over2}\] so that means that its...\[(x+{14\over3})~~~and~~~(x+{9\over2})\]so to make those 'unfractioned we'll multiply by the denominators:\[\large(3x+14)(2x+9)\] tada! :D
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
@Jeans123 hope that helps! :)
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
I have been proved wrong. @yummydum that was smart to use the quadratic. He found the solutions for x so he knew what the other terms had to be. Then he got rid of the fractions by multiplying by the denominator
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
Sry just habbit of typing, didn't mean anything by it
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
Thank you both of you he and she;)
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
no harm :) ...Youre Welcome Austin! :) feel free to ask more anytime you need help (when im there of course :))
 one year ago

Jeans123 Group TitleBest ResponseYou've already chosen the best response.0
In about five minutes I will:)
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.2
i leave pretty soon so ask now if you can :)
 one year ago
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