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why a system of equations must have at least as many equations as there are variables to have a single solution?
 one year ago
 one year ago
why a system of equations must have at least as many equations as there are variables to have a single solution?
 one year ago
 one year ago

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richywBest ResponseYou've already chosen the best response.0
the rank of the column space= the rank of the row space, so there will be an infinite number of solutions.
 one year ago

richywBest ResponseYou've already chosen the best response.0
or you can think of it like two planes cannot intersect at a point, they can only intersect in a line.
 one year ago

nazarfjBest ResponseYou've already chosen the best response.0
sorry but i dont get it can you explain more please
 one year ago

henpenBest ResponseYou've already chosen the best response.1
In 2 dimensions, if you have ax+by=c and px+qy=r, then these two lines will intersect once (that is, you know the point of intersection). If you had 1 line, you wouldn't know the point of intersection as there is no other line to compare it to. The point of intersection could be on any point on the line given.
 one year ago

henpenBest ResponseYou've already chosen the best response.1
In 3 dimensions, if you have 2 equations it is not enough. That is, ax+by+cz=d and px+qy+rz=s will not give you one point of intersection, but a line (similar to 2 dimensions + 1 equation: when you are 1 equation too few, you get a line of intersection, not a point). If you have 2 equations too few, you get a plane of intersections (e.g. in 3D having just ax+by+cz=d).
 one year ago

nazarfjBest ResponseYou've already chosen the best response.0
thanks a lot mannn you really helped me, not just helped me you saved my life lol this question had a big bones :D i appreciate it
 one year ago
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