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both part a and b are asking you to find the time t for a given h. for a, solve the following equations for t: -16t^2 + 1700 = 1000
t=(close to) 1.654 is what I got a.
I got t = 6.614 -16t^2 +1700 = 1000 -16t^2 = -700 t^2 = 43.75 then take square root of both sides
1000=-16t^2+1700 -700=-16t^2 _/-700=_/-16t^2 26.458/16=16t/16 t=1.654 is what I did
You need to divide by 16 first, before you take the square root.
Okay got a. and b. now I just need c.:)
Domain = what values of time would be used here? t > 0, since negative time not reasonable. And you probably need to find when the ball hits the ground, since after that time, the ball would be underground.
1700=16t^2 _/-106.25=t^2 t=10.3078 Is what I got for how long it takes to hit the ground.
Cool. So the a reasonable domain is from 0 to 10.3078.
Range: what values of height seem reasonable? h > 0, because negative height would mean that the ball was underground. And ... since the ball was "dropped" from a height of 1700 (vs being "thrown up" from a height) the maximum height would be 1700. So ... a reasonable range would be from 0 to 1700.|dw:1352328021424:dw|
Thank you that helped a lot! I have one more question to post can you help me with it?
sure, I'll look for you.