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the head of the sledge hammer weighs 22N and is moving at a speed of 7.6m/s when it strikes a skate.The skate moves 0.025m in to the ground in response. assume that forty % of the hammer kinetic energy is converted to initial kinetic energy of teh skate. apply teh work-energy theorem and obtain teh average resistive force applied to teh skate by the ground
Can we use g = 10 for ease?
ok i already did that part M=2.2kg V=7.6m/s d=0.025m

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mass of hammer = 2.2kg KE of hammer = 0.5 m v^2 times this by 0.6 to give the energy used by the skate to do work on the floor. Then, force = work done / distance.
instead of that can i use |dw:1352333068253:dw|

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