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ksaimouli
 3 years ago
help
ksaimouli
 3 years ago
help

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ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.1the head of the sledge hammer weighs 22N and is moving at a speed of 7.6m/s when it strikes a skate.The skate moves 0.025m in to the ground in response. assume that forty % of the hammer kinetic energy is converted to initial kinetic energy of teh skate. apply teh workenergy theorem and obtain teh average resistive force applied to teh skate by the ground

furnessj
 3 years ago
Best ResponseYou've already chosen the best response.0Can we use g = 10 for ease?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.1ok i already did that part M=2.2kg V=7.6m/s d=0.025m

furnessj
 3 years ago
Best ResponseYou've already chosen the best response.0mass of hammer = 2.2kg KE of hammer = 0.5 m v^2 times this by 0.6 to give the energy used by the skate to do work on the floor. Then, force = work done / distance.

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.1instead of that can i use dw:1352333068253:dw
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