anonymous
  • anonymous
I only need help with #2. The image of the question attached
Chemistry
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Preetha
  • Preetha
First you write the balanced eq out. H2SO4+2KOH --> K2So4+2H2O Moles of H2SO4 = 25 ml/1000 x 0.125 Moles/L NExt the stoichiometric ratio 1 mole of H2SO4 = 2 Moles of KOH So moles of KOH = moles of H2SO4 x 2 moles KOH/1 mole H2SO4 Now M of KOH = moles (from the previous step) / (27.07 ml /1000ml)L
anonymous
  • anonymous
Is that how u find teh concentration of it ?

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anonymous
  • anonymous
As in does that response give u teh concentration on KOH?
Preetha
  • Preetha
What is M? MOlarity. Or concentration.
anonymous
  • anonymous
Molarity
anonymous
  • anonymous
So M of KOH must mean molarity which is a way to express concentration. Am i understanding it correctly

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