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help_needed

  • 3 years ago

I only need help with #2. The image of the question attached

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  1. help_needed
    • 3 years ago
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  2. Preetha
    • 3 years ago
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    First you write the balanced eq out. H2SO4+2KOH --> K2So4+2H2O Moles of H2SO4 = 25 ml/1000 x 0.125 Moles/L NExt the stoichiometric ratio 1 mole of H2SO4 = 2 Moles of KOH So moles of KOH = moles of H2SO4 x 2 moles KOH/1 mole H2SO4 Now M of KOH = moles (from the previous step) / (27.07 ml /1000ml)L

  3. help_needed
    • 3 years ago
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    Is that how u find teh concentration of it ?

  4. help_needed
    • 3 years ago
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    As in does that response give u teh concentration on KOH?

  5. Preetha
    • 3 years ago
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    What is M? MOlarity. Or concentration.

  6. help_needed
    • 3 years ago
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    Molarity

  7. help_needed
    • 3 years ago
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    So M of KOH must mean molarity which is a way to express concentration. Am i understanding it correctly

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