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help_needed
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I only need help with #2. The image of the question attached
 2 years ago
 2 years ago
help_needed Group Title
I only need help with #2. The image of the question attached
 2 years ago
 2 years ago

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Preetha Group TitleBest ResponseYou've already chosen the best response.1
First you write the balanced eq out. H2SO4+2KOH > K2So4+2H2O Moles of H2SO4 = 25 ml/1000 x 0.125 Moles/L NExt the stoichiometric ratio 1 mole of H2SO4 = 2 Moles of KOH So moles of KOH = moles of H2SO4 x 2 moles KOH/1 mole H2SO4 Now M of KOH = moles (from the previous step) / (27.07 ml /1000ml)L
 2 years ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
Is that how u find teh concentration of it ?
 2 years ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
As in does that response give u teh concentration on KOH?
 2 years ago

Preetha Group TitleBest ResponseYou've already chosen the best response.1
What is M? MOlarity. Or concentration.
 2 years ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
Molarity
 2 years ago

help_needed Group TitleBest ResponseYou've already chosen the best response.0
So M of KOH must mean molarity which is a way to express concentration. Am i understanding it correctly
 2 years ago
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