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this is linear
do you know how to use an integrating factor?

how far did you get?

also, how do I handle the absolute value that gets kicked out of a logarithmic function?

yes, but am I solving y=(2/5)x+c or am i solving y=(2/5)x+cx^-4?

y=(2/5)x+cx^-4?

from this: yx^4=(2/5)x^5+c
do I go to y=(2/5)x + c
or y=(2/5)x+cx^-4?

which can also be written as y=(2/5)x+c/(x^4)

yes, that is correct

which one? the second one?

oh I see, I didn't mean to copy the '?'
the second one is right
y=(2/5)x+cx^-4=(2/5)x+c/(x^4)

gotcha, thank you! I appreciate that. makes life a whole lot easier. lol

from there applying initial conditions is a piece of cake!

thanks for your help man(or woman), I really appreciate it.

no problem