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Napervillian
Group Title
solve this differential equation:
y'+(4/x)y = 2
initial condition: y(1)=4
 2 years ago
 2 years ago
Napervillian Group Title
solve this differential equation: y'+(4/x)y = 2 initial condition: y(1)=4
 2 years ago
 2 years ago

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TuringTest Group TitleBest ResponseYou've already chosen the best response.1
this is linear do you know how to use an integrating factor?
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
yes, i have solved it but it has been a long time and I can't remember how to handle the constant c that I get out of my integral
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
how far did you get?
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
I have an answer, but when I get to this part: yx^4=(2/5)x^5+c I'm not sure if I also apply my x^4 to the c or leave it as a constant
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
also, how do I handle the absolute value that gets kicked out of a logarithmic function?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
if you want the "explicit" solution, solve for y y(1)=4 means you can plug in x=1 and y=4, which will allow you to solve for c
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
yes, but am I solving y=(2/5)x+c or am i solving y=(2/5)x+cx^4?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
y=(2/5)x+cx^4?
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
from this: yx^4=(2/5)x^5+c do I go to y=(2/5)x + c or y=(2/5)x+cx^4?
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
which can also be written as y=(2/5)x+c/(x^4)
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
yes, that is correct
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
which one? the second one?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
oh I see, I didn't mean to copy the '?' the second one is right y=(2/5)x+cx^4=(2/5)x+c/(x^4)
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
gotcha, thank you! I appreciate that. makes life a whole lot easier. lol
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
from there applying initial conditions is a piece of cake!
 2 years ago

Napervillian Group TitleBest ResponseYou've already chosen the best response.0
thanks for your help man(or woman), I really appreciate it.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
no problem
 2 years ago
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