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## alyssababy7 3 years ago Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 - 10x - 8y + 29 = 0 A. (x - 5)^2 +(y - 4)^2 = 12 (5, 4), r = 12 B. (x - 5)^2 +(y - 4)^2 = 12 (5, 4), r = 2 sq rt 3 C. (x + 5)^2 +(y + 4)^2 = 12 (-5, -4), r = 2 sq rt 3

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1. Reaper534

is this calculis

2. alyssababy7

Yes pre-calc

3. satellite73

start with $x^2 + y^2 - 10x - 8y + 29 = 0$ then group the terms together as $x^2-10x+y^2-8y=-29$ to complete the square, take half the coefficient of the $$x$$ and $$y$$ term and write $(x-5)^2+(y-8)^2=-29+5^2+4^2$ then compute the number on the right

4. Reaper534

ooh thats y im in geometry srry

5. satellite73

you get $(x-5)^2+(y-4)^2=12$ so the circle has center at $$(5,4)$$ and radius $$\sqrt{12}$$ or $$2\sqrt{3}$$ if you prefer

6. alyssababy7

thank you

7. satellite73

yw

8. Reaper534

see u marrow alyssa :) bye

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