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alyssababy7
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Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x^2 + y^2  10x  8y + 29 = 0
A. (x  5)^2 +(y  4)^2 = 12 (5, 4), r = 12
B. (x  5)^2 +(y  4)^2 = 12 (5, 4), r = 2 sq rt 3
C. (x + 5)^2 +(y + 4)^2 = 12 (5, 4), r = 2 sq rt 3
 2 years ago
 2 years ago
alyssababy7 Group Title
Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2  10x  8y + 29 = 0 A. (x  5)^2 +(y  4)^2 = 12 (5, 4), r = 12 B. (x  5)^2 +(y  4)^2 = 12 (5, 4), r = 2 sq rt 3 C. (x + 5)^2 +(y + 4)^2 = 12 (5, 4), r = 2 sq rt 3
 2 years ago
 2 years ago

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Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
is this calculis
 2 years ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
Yes precalc
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
start with \[x^2 + y^2  10x  8y + 29 = 0\] then group the terms together as \[x^210x+y^28y=29\] to complete the square, take half the coefficient of the \(x\) and \(y\) term and write \[(x5)^2+(y8)^2=29+5^2+4^2\] then compute the number on the right
 2 years ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
ooh thats y im in geometry srry
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you get \[(x5)^2+(y4)^2=12\] so the circle has center at \((5,4)\) and radius \(\sqrt{12}\) or \(2\sqrt{3}\) if you prefer
 2 years ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
thank you
 2 years ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
see u marrow alyssa :) bye
 2 years ago
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