A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352343487773:dw

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0how do I long divide this to find the vertical asymptote of the function and the range ?

seitys
 2 years ago
Best ResponseYou've already chosen the best response.0Remember that you can divide in parts so that (3x1)/x is the same as (3x/x)  (1/x). The 3x/x can be simplified to 3. When you graph this function, it is just 1/x shifted up 3 spaces. For example if x = 1, y = 3 + 1/1 = 4. As for the asymptote, it is at x = 0 because 1/x is not defined when x = 0.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1(long division is for horizontal or slant asymptotes, not vertical asymptotes, but yeah, that's a way to do it.)

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1352347692738:dw

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0how did you get 1/3 ? :S

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Vertical asymptotes are where the denominator is equal to zero.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1If you meant as your function, \[\large \frac{3x1}{x}\] Then the vertical asymptote is at x=0. You only use long division to find slant asymptotes.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.