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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352343487773:dw

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0how do I long divide this to find the vertical asymptote of the function and the range ?

seitys
 2 years ago
Best ResponseYou've already chosen the best response.0Remember that you can divide in parts so that (3x1)/x is the same as (3x/x)  (1/x). The 3x/x can be simplified to 3. When you graph this function, it is just 1/x shifted up 3 spaces. For example if x = 1, y = 3 + 1/1 = 4. As for the asymptote, it is at x = 0 because 1/x is not defined when x = 0.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1(long division is for horizontal or slant asymptotes, not vertical asymptotes, but yeah, that's a way to do it.)

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1352347692738:dw

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0how did you get 1/3 ? :S

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Vertical asymptotes are where the denominator is equal to zero.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1If you meant as your function, \[\large \frac{3x1}{x}\] Then the vertical asymptote is at x=0. You only use long division to find slant asymptotes.
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