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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352343487773:dw
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
vertical asymptote
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
how do I long divide this to find the vertical asymptote of the function and the range ?
 2 years ago

seitys Group TitleBest ResponseYou've already chosen the best response.0
Remember that you can divide in parts so that (3x1)/x is the same as (3x/x)  (1/x). The 3x/x can be simplified to 3. When you graph this function, it is just 1/x shifted up 3 spaces. For example if x = 1, y = 3 + 1/1 = 4. As for the asymptote, it is at x = 0 because 1/x is not defined when x = 0.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(long division is for horizontal or slant asymptotes, not vertical asymptotes, but yeah, that's a way to do it.)
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
dw:1352347692738:dw
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
how did you get 1/3 ? :S
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Vertical asymptotes are where the denominator is equal to zero.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
If you meant as your function, \[\large \frac{3x1}{x}\] Then the vertical asymptote is at x=0. You only use long division to find slant asymptotes.
 2 years ago
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