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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352343487773:dw
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
vertical asymptote
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
how do I long divide this to find the vertical asymptote of the function and the range ?
 one year ago

seitys Group TitleBest ResponseYou've already chosen the best response.0
Remember that you can divide in parts so that (3x1)/x is the same as (3x/x)  (1/x). The 3x/x can be simplified to 3. When you graph this function, it is just 1/x shifted up 3 spaces. For example if x = 1, y = 3 + 1/1 = 4. As for the asymptote, it is at x = 0 because 1/x is not defined when x = 0.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(long division is for horizontal or slant asymptotes, not vertical asymptotes, but yeah, that's a way to do it.)
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
dw:1352347692738:dw
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
how did you get 1/3 ? :S
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Vertical asymptotes are where the denominator is equal to zero.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
If you meant as your function, \[\large \frac{3x1}{x}\] Then the vertical asymptote is at x=0. You only use long division to find slant asymptotes.
 one year ago
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