Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

LOG(b2) 3rdroot/2 (typed version after the jump)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

\[\log _{2} \sqrt[3]{2}\]
|dw:1352348272404:dw|
What can you do next?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

get rid of the base 2 and the two in the parenthesis?
You have a power in a log.
|dw:1352348442988:dw|
hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x
Lot harder...
|dw:1352348582297:dw|
|dw:1352348653250:dw| and then...
Okay that works too...
My way is a lot easier I think though.
|dw:1352348698633:dw|
cool, do you think you could come up with a new example that would work?
Sure.
awesome, that way I can get a fresh go at it
|dw:1352348747232:dw|
Try that.
That's a pi/4 btw.
hm, ok...
|dw:1352348848985:dw| I did it her way, just cuz I've been doing that other one like that...
Okay fine. :p . Hmm...
that anything close to being correct? haha
It is correct.
|dw:1352349005378:dw|
That's a 2*pi btwe.
btw*
ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?
yeah :p .
I prefer exact answers but sure.
I think you get the point though so I will stop. Good job :) .
haha, this whole concept of log is just really new and confusing to me
You are doing fine :) .
I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one
|dw:1352349332360:dw| pretty sure I messed that up
Yeah you did :P .
haha
|dw:1352349512686:dw|
That was 2 * pi not 2*x*pi .
Anyways, I am getting ahead of myself. You will learn all this soon.
probably so haha. see if you can help me with one like this...
|dw:1352349693033:dw|
|dw:1352349742608:dw|
I should mention: |dw:1352349777605:dw|
log base a to the ath power equals 1?
Log base a of a is 1.
how did you get 1/25 to 5^-5
Reciprocal values.
Sorry I should have said 5^-2.
|dw:1352349972862:dw|
ah
|dw:1352349999623:dw|
ok I see
|dw:1352350166704:dw| so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.
Well Like I said: |dw:1352350268114:dw|
Proof:|dw:1352350284036:dw|
haha, I feel like I'm so close to getting that.
Okay we know that logs are the inverse of exponential function right?
|dw:1352350446240:dw|
instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?
Not really...
Logarithms are just the inverse functions of exponential functions.
I'm not quiet sure I follow. I'm close though ha
Okay. |dw:1352350715897:dw|
They are simply inverses.
so like 5^2 is 25, the inverse would be 25 something =5?
the "something" is the part that I'm missing lol
|dw:1352350885891:dw|
awesome, now if I can just remember that. :-)
You will :) .
I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it
I don't know why thats so difficult for me. it's very annoying
I found logs hard the first time too :) .It's fine. You will get the hang of it.
my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it
Same Same... I find doing practice problems helps the most.
yea. just trying to take my time and get it to develop into a solid understanding.
|dw:1352351467721:dw| ok, I'm going to try this one, I think I might have it
|dw:1352351563158:dw|
dang. thats not quite it... forgot I had the answer sheet
That right! :O .
Oh, youre right, I just didn't follow it through to x=32 like she did
|dw:1352352361556:dw| it's starting to make a little sense finally
Yep correct :) .
|dw:1352352553761:dw| do I need to multiply the fraction out?
No.
|dw:1352352659947:dw| I'm stuck on the 3rd root part
|dw:1352352937727:dw| isn't that how it works?
hm, no I did something wrong.
|dw:1352353487129:dw| well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.

Not the answer you are looking for?

Search for more explanations.

Ask your own question