LOG(b2) 3rdroot/2
(typed version after the jump)

- anonymous

LOG(b2) 3rdroot/2
(typed version after the jump)

- schrodinger

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- anonymous

\[\log _{2} \sqrt[3]{2}\]

- anonymous

|dw:1352348272404:dw|

- anonymous

What can you do next?

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## More answers

- anonymous

get rid of the base 2 and the two in the parenthesis?

- anonymous

You have a power in a log.

- anonymous

|dw:1352348442988:dw|

- anonymous

hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x

- anonymous

Lot harder...

- anonymous

|dw:1352348582297:dw|

- anonymous

|dw:1352348653250:dw| and then...

- anonymous

Okay that works too...

- anonymous

My way is a lot easier I think though.

- anonymous

|dw:1352348698633:dw|

- anonymous

cool, do you think you could come up with a new example that would work?

- anonymous

Sure.

- anonymous

awesome, that way I can get a fresh go at it

- anonymous

|dw:1352348747232:dw|

- anonymous

Try that.

- anonymous

That's a pi/4 btw.

- anonymous

hm, ok...

- anonymous

|dw:1352348848985:dw| I did it her way, just cuz I've been doing that other one like that...

- anonymous

Okay fine. :p . Hmm...

- anonymous

that anything close to being correct? haha

- anonymous

It is correct.

- anonymous

|dw:1352349005378:dw|

- anonymous

That's a 2*pi btwe.

- anonymous

btw*

- anonymous

ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?

- anonymous

yeah :p .

- anonymous

I prefer exact answers but sure.

- anonymous

I think you get the point though so I will stop. Good job :) .

- anonymous

haha, this whole concept of log is just really new and confusing to me

- anonymous

You are doing fine :) .

- anonymous

I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one

- anonymous

|dw:1352349332360:dw| pretty sure I messed that up

- anonymous

Yeah you did :P .

- anonymous

haha

- anonymous

|dw:1352349512686:dw|

- anonymous

That was 2 * pi not 2*x*pi .

- anonymous

Anyways, I am getting ahead of myself. You will learn all this soon.

- anonymous

probably so haha. see if you can help me with one like this...

- anonymous

|dw:1352349693033:dw|

- anonymous

|dw:1352349742608:dw|

- anonymous

I should mention:
|dw:1352349777605:dw|

- anonymous

log base a to the ath power equals 1?

- anonymous

Log base a of a is 1.

- anonymous

how did you get 1/25 to 5^-5

- anonymous

Reciprocal values.

- anonymous

Sorry I should have said 5^-2.

- anonymous

|dw:1352349972862:dw|

- anonymous

ah

- anonymous

|dw:1352349999623:dw|

- anonymous

ok I see

- anonymous

|dw:1352350166704:dw| so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.

- anonymous

Well Like I said:
|dw:1352350268114:dw|

- anonymous

Proof:|dw:1352350284036:dw|

- anonymous

haha, I feel like I'm so close to getting that.

- anonymous

Okay we know that logs are the inverse of exponential function right?

- anonymous

|dw:1352350446240:dw|

- anonymous

instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?

- anonymous

Not really...

- anonymous

Logarithms are just the inverse functions of exponential functions.

- anonymous

I'm not quiet sure I follow. I'm close though ha

- anonymous

Okay. |dw:1352350715897:dw|

- anonymous

They are simply inverses.

- anonymous

so like 5^2 is 25, the inverse would be 25 something =5?

- anonymous

the "something" is the part that I'm missing lol

- anonymous

|dw:1352350885891:dw|

- anonymous

awesome, now if I can just remember that. :-)

- anonymous

You will :) .

- anonymous

I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it

- anonymous

I don't know why thats so difficult for me. it's very annoying

- anonymous

I found logs hard the first time too :) .It's fine. You will get the hang of it.

- anonymous

my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it

- anonymous

Same Same... I find doing practice problems helps the most.

- anonymous

yea. just trying to take my time and get it to develop into a solid understanding.

- anonymous

|dw:1352351467721:dw| ok, I'm going to try this one, I think I might have it

- anonymous

|dw:1352351563158:dw|

- anonymous

dang. thats not quite it... forgot I had the answer sheet

- anonymous

That right! :O .

- anonymous

Oh, youre right, I just didn't follow it through to x=32 like she did

- anonymous

|dw:1352352361556:dw| it's starting to make a little sense finally

- anonymous

Yep correct :) .

- anonymous

|dw:1352352553761:dw| do I need to multiply the fraction out?

- anonymous

No.

- anonymous

|dw:1352352659947:dw| I'm stuck on the 3rd root part

- anonymous

|dw:1352352937727:dw| isn't that how it works?

- anonymous

hm, no I did something wrong.

- anonymous

|dw:1352353487129:dw| well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.

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