brandonloves
LOG(b2) 3rdroot/2
(typed version after the jump)
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brandonloves
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\[\log _{2} \sqrt[3]{2}\]
Dido525
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|dw:1352348272404:dw|
Dido525
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What can you do next?
brandonloves
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get rid of the base 2 and the two in the parenthesis?
Dido525
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You have a power in a log.
Dido525
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|dw:1352348442988:dw|
brandonloves
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hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x
Dido525
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Lot harder...
brandonloves
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|dw:1352348582297:dw|
brandonloves
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|dw:1352348653250:dw| and then...
Dido525
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Okay that works too...
Dido525
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My way is a lot easier I think though.
Dido525
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|dw:1352348698633:dw|
brandonloves
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cool, do you think you could come up with a new example that would work?
Dido525
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Sure.
brandonloves
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awesome, that way I can get a fresh go at it
Dido525
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|dw:1352348747232:dw|
Dido525
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Try that.
Dido525
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That's a pi/4 btw.
brandonloves
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hm, ok...
brandonloves
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|dw:1352348848985:dw| I did it her way, just cuz I've been doing that other one like that...
Dido525
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Okay fine. :p . Hmm...
brandonloves
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that anything close to being correct? haha
Dido525
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It is correct.
Dido525
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|dw:1352349005378:dw|
Dido525
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That's a 2*pi btwe.
Dido525
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btw*
brandonloves
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ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?
Dido525
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yeah :p .
Dido525
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I prefer exact answers but sure.
Dido525
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I think you get the point though so I will stop. Good job :) .
brandonloves
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haha, this whole concept of log is just really new and confusing to me
Dido525
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You are doing fine :) .
brandonloves
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I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one
brandonloves
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|dw:1352349332360:dw| pretty sure I messed that up
Dido525
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Yeah you did :P .
brandonloves
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haha
Dido525
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|dw:1352349512686:dw|
Dido525
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That was 2 * pi not 2*x*pi .
Dido525
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Anyways, I am getting ahead of myself. You will learn all this soon.
brandonloves
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probably so haha. see if you can help me with one like this...
brandonloves
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|dw:1352349693033:dw|
Dido525
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|dw:1352349742608:dw|
Dido525
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I should mention:
|dw:1352349777605:dw|
brandonloves
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log base a to the ath power equals 1?
Dido525
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Log base a of a is 1.
brandonloves
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how did you get 1/25 to 5^-5
Dido525
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Reciprocal values.
Dido525
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Sorry I should have said 5^-2.
Dido525
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|dw:1352349972862:dw|
brandonloves
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ah
Dido525
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|dw:1352349999623:dw|
brandonloves
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ok I see
brandonloves
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|dw:1352350166704:dw| so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.
Dido525
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Well Like I said:
|dw:1352350268114:dw|
Dido525
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Proof:|dw:1352350284036:dw|
brandonloves
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haha, I feel like I'm so close to getting that.
Dido525
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Okay we know that logs are the inverse of exponential function right?
Dido525
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|dw:1352350446240:dw|
brandonloves
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instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?
Dido525
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Not really...
Dido525
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Logarithms are just the inverse functions of exponential functions.
brandonloves
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I'm not quiet sure I follow. I'm close though ha
Dido525
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Okay. |dw:1352350715897:dw|
Dido525
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They are simply inverses.
brandonloves
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so like 5^2 is 25, the inverse would be 25 something =5?
brandonloves
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the "something" is the part that I'm missing lol
Dido525
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|dw:1352350885891:dw|
brandonloves
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awesome, now if I can just remember that. :-)
Dido525
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You will :) .
brandonloves
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I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it
brandonloves
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I don't know why thats so difficult for me. it's very annoying
Dido525
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I found logs hard the first time too :) .It's fine. You will get the hang of it.
brandonloves
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my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it
Dido525
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Same Same... I find doing practice problems helps the most.
brandonloves
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yea. just trying to take my time and get it to develop into a solid understanding.
brandonloves
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|dw:1352351467721:dw| ok, I'm going to try this one, I think I might have it
brandonloves
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|dw:1352351563158:dw|
brandonloves
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dang. thats not quite it... forgot I had the answer sheet
Dido525
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That right! :O .
brandonloves
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Oh, youre right, I just didn't follow it through to x=32 like she did
brandonloves
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|dw:1352352361556:dw| it's starting to make a little sense finally
Dido525
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Yep correct :) .
brandonloves
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|dw:1352352553761:dw| do I need to multiply the fraction out?
Dido525
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No.
brandonloves
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|dw:1352352659947:dw| I'm stuck on the 3rd root part
brandonloves
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|dw:1352352937727:dw| isn't that how it works?
brandonloves
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hm, no I did something wrong.
brandonloves
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|dw:1352353487129:dw| well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.