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brandonloves
 3 years ago
LOG(b2) 3rdroot/2
(typed version after the jump)
brandonloves
 3 years ago
LOG(b2) 3rdroot/2 (typed version after the jump)

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brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0\[\log _{2} \sqrt[3]{2}\]

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0get rid of the base 2 and the two in the parenthesis?

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1You have a power in a log.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352348582297:dw

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352348653250:dw and then...

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1My way is a lot easier I think though.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0cool, do you think you could come up with a new example that would work?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0awesome, that way I can get a fresh go at it

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352348848985:dw I did it her way, just cuz I've been doing that other one like that...

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0that anything close to being correct? haha

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1I prefer exact answers but sure.

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1I think you get the point though so I will stop. Good job :) .

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0haha, this whole concept of log is just really new and confusing to me

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1You are doing fine :) .

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352349332360:dw pretty sure I messed that up

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1That was 2 * pi not 2*x*pi .

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Anyways, I am getting ahead of myself. You will learn all this soon.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0probably so haha. see if you can help me with one like this...

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352349693033:dw

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1I should mention: dw:1352349777605:dw

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0log base a to the ath power equals 1?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get 1/25 to 5^5

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry I should have said 5^2.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352350166704:dw so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Well Like I said: dw:1352350268114:dw

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Proof:dw:1352350284036:dw

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0haha, I feel like I'm so close to getting that.

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Okay we know that logs are the inverse of exponential function right?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Logarithms are just the inverse functions of exponential functions.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not quiet sure I follow. I'm close though ha

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Okay. dw:1352350715897:dw

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1They are simply inverses.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0so like 5^2 is 25, the inverse would be 25 something =5?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0the "something" is the part that I'm missing lol

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0awesome, now if I can just remember that. :)

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know why thats so difficult for me. it's very annoying

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1I found logs hard the first time too :) .It's fine. You will get the hang of it.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it

Dido525
 3 years ago
Best ResponseYou've already chosen the best response.1Same Same... I find doing practice problems helps the most.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0yea. just trying to take my time and get it to develop into a solid understanding.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352351467721:dw ok, I'm going to try this one, I think I might have it

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352351563158:dw

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dang. thats not quite it... forgot I had the answer sheet

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, youre right, I just didn't follow it through to x=32 like she did

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352352361556:dw it's starting to make a little sense finally

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352352553761:dw do I need to multiply the fraction out?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352352659947:dw I'm stuck on the 3rd root part

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352352937727:dw isn't that how it works?

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0hm, no I did something wrong.

brandonloves
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352353487129:dw well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.
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