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brandonloves

  • 2 years ago

LOG(b2) 3rdroot/2 (typed version after the jump)

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  1. brandonloves
    • 2 years ago
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    \[\log _{2} \sqrt[3]{2}\]

  2. Dido525
    • 2 years ago
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    |dw:1352348272404:dw|

  3. Dido525
    • 2 years ago
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    What can you do next?

  4. brandonloves
    • 2 years ago
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    get rid of the base 2 and the two in the parenthesis?

  5. Dido525
    • 2 years ago
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    You have a power in a log.

  6. Dido525
    • 2 years ago
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    |dw:1352348442988:dw|

  7. brandonloves
    • 2 years ago
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    hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x

  8. Dido525
    • 2 years ago
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    Lot harder...

  9. brandonloves
    • 2 years ago
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    |dw:1352348582297:dw|

  10. brandonloves
    • 2 years ago
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    |dw:1352348653250:dw| and then...

  11. Dido525
    • 2 years ago
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    Okay that works too...

  12. Dido525
    • 2 years ago
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    My way is a lot easier I think though.

  13. Dido525
    • 2 years ago
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    |dw:1352348698633:dw|

  14. brandonloves
    • 2 years ago
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    cool, do you think you could come up with a new example that would work?

  15. Dido525
    • 2 years ago
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    Sure.

  16. brandonloves
    • 2 years ago
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    awesome, that way I can get a fresh go at it

  17. Dido525
    • 2 years ago
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    |dw:1352348747232:dw|

  18. Dido525
    • 2 years ago
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    Try that.

  19. Dido525
    • 2 years ago
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    That's a pi/4 btw.

  20. brandonloves
    • 2 years ago
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    hm, ok...

  21. brandonloves
    • 2 years ago
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    |dw:1352348848985:dw| I did it her way, just cuz I've been doing that other one like that...

  22. Dido525
    • 2 years ago
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    Okay fine. :p . Hmm...

  23. brandonloves
    • 2 years ago
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    that anything close to being correct? haha

  24. Dido525
    • 2 years ago
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    It is correct.

  25. Dido525
    • 2 years ago
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    |dw:1352349005378:dw|

  26. Dido525
    • 2 years ago
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    That's a 2*pi btwe.

  27. Dido525
    • 2 years ago
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    btw*

  28. brandonloves
    • 2 years ago
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    ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?

  29. Dido525
    • 2 years ago
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    yeah :p .

  30. Dido525
    • 2 years ago
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    I prefer exact answers but sure.

  31. Dido525
    • 2 years ago
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    I think you get the point though so I will stop. Good job :) .

  32. brandonloves
    • 2 years ago
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    haha, this whole concept of log is just really new and confusing to me

  33. Dido525
    • 2 years ago
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    You are doing fine :) .

  34. brandonloves
    • 2 years ago
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    I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one

  35. brandonloves
    • 2 years ago
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    |dw:1352349332360:dw| pretty sure I messed that up

  36. Dido525
    • 2 years ago
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    Yeah you did :P .

  37. brandonloves
    • 2 years ago
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    haha

  38. Dido525
    • 2 years ago
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    |dw:1352349512686:dw|

  39. Dido525
    • 2 years ago
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    That was 2 * pi not 2*x*pi .

  40. Dido525
    • 2 years ago
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    Anyways, I am getting ahead of myself. You will learn all this soon.

  41. brandonloves
    • 2 years ago
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    probably so haha. see if you can help me with one like this...

  42. brandonloves
    • 2 years ago
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    |dw:1352349693033:dw|

  43. Dido525
    • 2 years ago
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    |dw:1352349742608:dw|

  44. Dido525
    • 2 years ago
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    I should mention: |dw:1352349777605:dw|

  45. brandonloves
    • 2 years ago
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    log base a to the ath power equals 1?

  46. Dido525
    • 2 years ago
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    Log base a of a is 1.

  47. brandonloves
    • 2 years ago
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    how did you get 1/25 to 5^-5

  48. Dido525
    • 2 years ago
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    Reciprocal values.

  49. Dido525
    • 2 years ago
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    Sorry I should have said 5^-2.

  50. Dido525
    • 2 years ago
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    |dw:1352349972862:dw|

  51. brandonloves
    • 2 years ago
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    ah

  52. Dido525
    • 2 years ago
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    |dw:1352349999623:dw|

  53. brandonloves
    • 2 years ago
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    ok I see

  54. brandonloves
    • 2 years ago
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    |dw:1352350166704:dw| so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.

  55. Dido525
    • 2 years ago
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    Well Like I said: |dw:1352350268114:dw|

  56. Dido525
    • 2 years ago
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    Proof:|dw:1352350284036:dw|

  57. brandonloves
    • 2 years ago
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    haha, I feel like I'm so close to getting that.

  58. Dido525
    • 2 years ago
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    Okay we know that logs are the inverse of exponential function right?

  59. Dido525
    • 2 years ago
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    |dw:1352350446240:dw|

  60. brandonloves
    • 2 years ago
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    instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?

  61. Dido525
    • 2 years ago
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    Not really...

  62. Dido525
    • 2 years ago
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    Logarithms are just the inverse functions of exponential functions.

  63. brandonloves
    • 2 years ago
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    I'm not quiet sure I follow. I'm close though ha

  64. Dido525
    • 2 years ago
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    Okay. |dw:1352350715897:dw|

  65. Dido525
    • 2 years ago
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    They are simply inverses.

  66. brandonloves
    • 2 years ago
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    so like 5^2 is 25, the inverse would be 25 something =5?

  67. brandonloves
    • 2 years ago
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    the "something" is the part that I'm missing lol

  68. Dido525
    • 2 years ago
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    |dw:1352350885891:dw|

  69. brandonloves
    • 2 years ago
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    awesome, now if I can just remember that. :-)

  70. Dido525
    • 2 years ago
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    You will :) .

  71. brandonloves
    • 2 years ago
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    I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it

  72. brandonloves
    • 2 years ago
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    I don't know why thats so difficult for me. it's very annoying

  73. Dido525
    • 2 years ago
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    I found logs hard the first time too :) .It's fine. You will get the hang of it.

  74. brandonloves
    • 2 years ago
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    my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it

  75. Dido525
    • 2 years ago
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    Same Same... I find doing practice problems helps the most.

  76. brandonloves
    • 2 years ago
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    yea. just trying to take my time and get it to develop into a solid understanding.

  77. brandonloves
    • 2 years ago
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    |dw:1352351467721:dw| ok, I'm going to try this one, I think I might have it

  78. brandonloves
    • 2 years ago
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    |dw:1352351563158:dw|

  79. brandonloves
    • 2 years ago
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    dang. thats not quite it... forgot I had the answer sheet

  80. Dido525
    • 2 years ago
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    That right! :O .

  81. brandonloves
    • 2 years ago
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    Oh, youre right, I just didn't follow it through to x=32 like she did

  82. brandonloves
    • 2 years ago
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    |dw:1352352361556:dw| it's starting to make a little sense finally

  83. Dido525
    • 2 years ago
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    Yep correct :) .

  84. brandonloves
    • 2 years ago
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    |dw:1352352553761:dw| do I need to multiply the fraction out?

  85. Dido525
    • 2 years ago
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    No.

  86. brandonloves
    • 2 years ago
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    |dw:1352352659947:dw| I'm stuck on the 3rd root part

  87. brandonloves
    • 2 years ago
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    |dw:1352352937727:dw| isn't that how it works?

  88. brandonloves
    • 2 years ago
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    hm, no I did something wrong.

  89. brandonloves
    • 2 years ago
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    |dw:1352353487129:dw| well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.

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