## brandonloves Group Title LOG(b2) 3rdroot/2 (typed version after the jump) 2 years ago 2 years ago

1. brandonloves

$\log _{2} \sqrt[3]{2}$

2. Dido525

|dw:1352348272404:dw|

3. Dido525

What can you do next?

4. brandonloves

get rid of the base 2 and the two in the parenthesis?

5. Dido525

You have a power in a log.

6. Dido525

|dw:1352348442988:dw|

7. brandonloves

hmm, ok. my teacher added an =X to it first, and then took off the log and made it 2^x

8. Dido525

Lot harder...

9. brandonloves

|dw:1352348582297:dw|

10. brandonloves

|dw:1352348653250:dw| and then...

11. Dido525

Okay that works too...

12. Dido525

My way is a lot easier I think though.

13. Dido525

|dw:1352348698633:dw|

14. brandonloves

cool, do you think you could come up with a new example that would work?

15. Dido525

Sure.

16. brandonloves

awesome, that way I can get a fresh go at it

17. Dido525

|dw:1352348747232:dw|

18. Dido525

Try that.

19. Dido525

That's a pi/4 btw.

20. brandonloves

hm, ok...

21. brandonloves

|dw:1352348848985:dw| I did it her way, just cuz I've been doing that other one like that...

22. Dido525

Okay fine. :p . Hmm...

23. brandonloves

that anything close to being correct? haha

24. Dido525

It is correct.

25. Dido525

|dw:1352349005378:dw|

26. Dido525

That's a 2*pi btwe.

27. Dido525

btw*

28. brandonloves

ok, I haven't done any of these with pi, so do I just treat it like a number, like 3.1416 or something?

29. Dido525

yeah :p .

30. Dido525

I prefer exact answers but sure.

31. Dido525

I think you get the point though so I will stop. Good job :) .

32. brandonloves

haha, this whole concept of log is just really new and confusing to me

33. Dido525

You are doing fine :) .

34. brandonloves

I'm just doing the steps as best I can, but I have no clue what it all means. hoping the understanding will come later lol. lemme see what I can do with that one

35. brandonloves

|dw:1352349332360:dw| pretty sure I messed that up

36. Dido525

Yeah you did :P .

37. brandonloves

haha

38. Dido525

|dw:1352349512686:dw|

39. Dido525

That was 2 * pi not 2*x*pi .

40. Dido525

Anyways, I am getting ahead of myself. You will learn all this soon.

41. brandonloves

probably so haha. see if you can help me with one like this...

42. brandonloves

|dw:1352349693033:dw|

43. Dido525

|dw:1352349742608:dw|

44. Dido525

I should mention: |dw:1352349777605:dw|

45. brandonloves

log base a to the ath power equals 1?

46. Dido525

Log base a of a is 1.

47. brandonloves

how did you get 1/25 to 5^-5

48. Dido525

Reciprocal values.

49. Dido525

Sorry I should have said 5^-2.

50. Dido525

|dw:1352349972862:dw|

51. brandonloves

ah

52. Dido525

|dw:1352349999623:dw|

53. brandonloves

ok I see

54. brandonloves

|dw:1352350166704:dw| so, on parts like this, are you actually "cancelling" the fives? thats how I've understood/been working them.

55. Dido525

Well Like I said: |dw:1352350268114:dw|

56. Dido525

Proof:|dw:1352350284036:dw|

57. brandonloves

haha, I feel like I'm so close to getting that.

58. Dido525

Okay we know that logs are the inverse of exponential function right?

59. Dido525

|dw:1352350446240:dw|

60. brandonloves

instead of like 1,2,3,4,5 they can represent a different measure of counting, is how I understand them. yes?

61. Dido525

Not really...

62. Dido525

Logarithms are just the inverse functions of exponential functions.

63. brandonloves

I'm not quiet sure I follow. I'm close though ha

64. Dido525

Okay. |dw:1352350715897:dw|

65. Dido525

They are simply inverses.

66. brandonloves

so like 5^2 is 25, the inverse would be 25 something =5?

67. brandonloves

the "something" is the part that I'm missing lol

68. Dido525

|dw:1352350885891:dw|

69. brandonloves

awesome, now if I can just remember that. :-)

70. Dido525

You will :) .

71. brandonloves

I guess I'm just trying to get my brain to read "log base 5 to the 25 equals 2" in a way that tells me exactly what i'm trying to do to it

72. brandonloves

I don't know why thats so difficult for me. it's very annoying

73. Dido525

I found logs hard the first time too :) .It's fine. You will get the hang of it.

74. brandonloves

my teacher goes really fast, so that doesn't help. I mostly just copy everything down, and don't have a chance to think about it

75. Dido525

Same Same... I find doing practice problems helps the most.

76. brandonloves

yea. just trying to take my time and get it to develop into a solid understanding.

77. brandonloves

|dw:1352351467721:dw| ok, I'm going to try this one, I think I might have it

78. brandonloves

|dw:1352351563158:dw|

79. brandonloves

80. Dido525

That right! :O .

81. brandonloves

Oh, youre right, I just didn't follow it through to x=32 like she did

82. brandonloves

|dw:1352352361556:dw| it's starting to make a little sense finally

83. Dido525

Yep correct :) .

84. brandonloves

|dw:1352352553761:dw| do I need to multiply the fraction out?

85. Dido525

No.

86. brandonloves

|dw:1352352659947:dw| I'm stuck on the 3rd root part

87. brandonloves

|dw:1352352937727:dw| isn't that how it works?

88. brandonloves

hm, no I did something wrong.

89. brandonloves

|dw:1352353487129:dw| well, I think that will be all I can do tonight. Thanks so much, you are awesome and I really appreciate it.