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chubbytots
Group Title
correct these calculations by changing either side of each equation.
a. (x+1)(2x+1) = x+2
 one year ago
 one year ago
chubbytots Group Title
correct these calculations by changing either side of each equation. a. (x+1)(2x+1) = x+2
 one year ago
 one year ago

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chubbytots Group TitleBest ResponseYou've already chosen the best response.0
\[(4p ^{2}3q)4(p ^{2}q)=7q\]
 one year ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
thats for b.
 one year ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
c. \[5k(k+1)(k ^{2}+5)=4k ^{2}\]
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
a. \[(x+1)(2x+1) = x+2\] Remove the parenthesis: \[x+12x1 = x+2\] Combine like terms: \[x2x+11 = x+2\]
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
b. Similarly to part a: \[(4p^2−3q)−4(p^2−q)=7q\] Remove parenthesis: \[4p^2−3q−4p^2+4q=7q\] Combine like terms: \[4p^2−4p^2−3q+4q=7q\]
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
c. \[5k(k+1)−(k^2+5)=4k^2\] Multiply out: \[5k^2 + 5k−(k^2+5)=4k^2\] Remove parenthesis: \[5k^2 + 5k−k^25=4k^2\] Combine like terms: \[5k^2−k^2 + 5k5=4k^2\]
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
As you can see, none of these are actually equivalent. You have to change one of the sides (usually a plus or minus or a constant) to make them correct.
 one year ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
ok :D thanks for helping :D
 one year ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
You're welcome. Glad I could help. ^_^
 one year ago
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