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chubbytots
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correct these calculations by changing either side of each equation.
a. (x+1)(2x+1) = x+2
 2 years ago
 2 years ago
chubbytots Group Title
correct these calculations by changing either side of each equation. a. (x+1)(2x+1) = x+2
 2 years ago
 2 years ago

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chubbytots Group TitleBest ResponseYou've already chosen the best response.0
\[(4p ^{2}3q)4(p ^{2}q)=7q\]
 2 years ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
thats for b.
 2 years ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
c. \[5k(k+1)(k ^{2}+5)=4k ^{2}\]
 2 years ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
a. \[(x+1)(2x+1) = x+2\] Remove the parenthesis: \[x+12x1 = x+2\] Combine like terms: \[x2x+11 = x+2\]
 2 years ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
b. Similarly to part a: \[(4p^2−3q)−4(p^2−q)=7q\] Remove parenthesis: \[4p^2−3q−4p^2+4q=7q\] Combine like terms: \[4p^2−4p^2−3q+4q=7q\]
 2 years ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
c. \[5k(k+1)−(k^2+5)=4k^2\] Multiply out: \[5k^2 + 5k−(k^2+5)=4k^2\] Remove parenthesis: \[5k^2 + 5k−k^25=4k^2\] Combine like terms: \[5k^2−k^2 + 5k5=4k^2\]
 2 years ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
As you can see, none of these are actually equivalent. You have to change one of the sides (usually a plus or minus or a constant) to make them correct.
 2 years ago

chubbytots Group TitleBest ResponseYou've already chosen the best response.0
ok :D thanks for helping :D
 2 years ago

LukeBlueFive Group TitleBest ResponseYou've already chosen the best response.1
You're welcome. Glad I could help. ^_^
 2 years ago
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