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Faman39 Group Title

A bakery charges $0.10 for a cookie that is 2 inches in diameter. If the price is proportional to the area, how much do they charge for an extra large cookie that is 10 inches in diameter? Assume that each cookie is shaped of a circle. $ 0.50 $ 1.00 $ 2.50 $ 12.50

  • 2 years ago
  • 2 years ago

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  1. Faman39 Group Title
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    @tkhunny can you able to help me with this ?

    • 2 years ago
  2. tkhunny Group Title
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    Here's the important part: "If the price is proportional to the area" Translate that Price = k*Area or just P = k*A. After that, there MUST be some given information. "$0.10 for a cookie that is 2 inches in diameter" There it is. Now what?

    • 2 years ago
  3. Faman39 Group Title
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    2.50 ?

    • 2 years ago
  4. tkhunny Group Title
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    Don't do that. You just went magically from a partially set up problem statement to a solution out of the air. Show your work and think it through. We have: P = k*A. and "$0.10 for a cookie that is 2 inches in diameter" Thus: 0.10 = k*pi*(2/2)^2 = k(pi) ==> k = 1/(10pi) Now what?

    • 2 years ago
  5. Faman39 Group Title
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    I m kinda confuse, you are saying multiply 2 three times then divide with 10, right?

    • 2 years ago
  6. tkhunny Group Title
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    No. You must read this problem very carefully. You are given the DIAMETER, but the relationship is with the AREA. You must convert. Diameter/2 = Radius. pi*Radius^2 = Area. It was mean of the question writer to use '2', since there were already two '2's in the development.

    • 2 years ago
  7. Faman39 Group Title
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    so 2 is it right?

    • 2 years ago
  8. Faman39 Group Title
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    oh ok thank you @tkhunny for helping, i will try another way

    • 2 years ago
  9. tkhunny Group Title
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    Once we ahve determiend 'k', we are nearly done. k = 1/(10pi) (1/10pi)*pi*(10/2)^2 = 25/10 = 2.50

    • 2 years ago
  10. Faman39 Group Title
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    It should second one?

    • 2 years ago
  11. Faman39 Group Title
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    i guess not

    • 2 years ago
  12. tkhunny Group Title
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    I don't understand the question. You just made me work the whole problem. It's 2.50.

    • 2 years ago
  13. Faman39 Group Title
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    I am sorry i could not get on beginning for network prob, now i went from up, where explain all, now i got. thanks so much @tkhunny !

    • 2 years ago
  14. Faman39 Group Title
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    So sorry for troubling :( i m really terrible

    • 2 years ago
  15. tkhunny Group Title
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    No name calling! Just spend the time it takes. You'll get it.

    • 2 years ago
  16. Faman39 Group Title
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    I am really sorry for everything :(

    • 2 years ago
  17. tkhunny Group Title
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    Read some material on "Direct Proportion". It's not impossible to learn it.

    • 2 years ago
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