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Faman39

  • 2 years ago

A bakery charges $0.10 for a cookie that is 2 inches in diameter. If the price is proportional to the area, how much do they charge for an extra large cookie that is 10 inches in diameter? Assume that each cookie is shaped of a circle. $ 0.50 $ 1.00 $ 2.50 $ 12.50

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  1. Faman39
    • 2 years ago
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    @mark_o. can you able to help me with this?

  2. Faman39
    • 2 years ago
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    @campbell_st can u able to help me wit this ?

  3. campbell_st
    • 2 years ago
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    ok... so what is the area of the small cookie d = 2inches so radius = 1 inch... can you find the area of a circular cookie with a radius of 1 inch..?

  4. Faman39
    • 2 years ago
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    I m not getting this prob at all, how to solve it :( dont know

  5. campbell_st
    • 2 years ago
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    ok the cookie is circular |dw:1352350196613:dw|

  6. campbell_st
    • 2 years ago
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    next you need to find the area of a cookie with diamater 10 inches of radius 5 inches... use \[A = \pi r^2\] can you do that..?

  7. campbell_st
    • 2 years ago
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    last step to find the cost x |dw:1352350411354:dw|

  8. Faman39
    • 2 years ago
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    Ok thank you :)

  9. Faman39
    • 2 years ago
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    I will try to figure out this

  10. mark_o.
    • 2 years ago
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    hi the question ask for how much is the bigger area cost? for small area of dia d=2 inch = cost $0.10 put it this way on the proportion cost $ x? = large A2 $0.10 = small A1 setting up the proportion will be cost $ x? large A2 -------- = ---------- $0.10 small A1 before that what is the small area A , the large area A2 ? use area of circle either A=pi d^2/4 or pi r^2 maybe you use dia d since it is alredy given

  11. mark_o.
    • 2 years ago
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    if for small area A1= pi d^2/4 A1= pi(2)^2/4 is A1= pi ? yes or no ? for large area A2=pi(10)^2/4 is A2=25 pi ? yes or no? if so plug them on your ratio cost $ x? large A2 -------- = ---------- $0.10 small A1 ($0.10 ) large A2 cost $ x? = x ---------- small A1 cost $ x=0.10(25 pi)/pi x= 0.10 (25)= $ 2.5 is it? yes ?

  12. mark_o.
    • 2 years ago
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    @ Faman39

  13. Faman39
    • 2 years ago
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    Got it thank you so so much :)

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