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Can someone explain to me, STEP BY STEP how to do this problem please, its Algebra 2-Complex numbers. -6(x+5)^2=120

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first divide both sides by -6 what u get ?
and u should know that \(\huge \sqrt{-1}=i\)
6(x+5)^2+120 = (x+5)^2 - 20i^2 =0 ( and then factorise ) as i^2 =-1

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Other answers:

hartn good explanation and asking for participation . well done !!
\[-6(x+5)^2=120\]\[(x+5)^2=-\frac{120}{6}\]\[x+5=\sqrt{-\frac{120}{6}}\]\[x+5=\sqrt{-20}\]\[x=\sqrt{-20}-5\]\[x=\sqrt{20}i-5\]\[x=\sqrt{4\cdot 5}i-5\]x=2\sqrt{5}i-5
Now take the square root of the RHS .
Don't just post the answer...
i don't think @CarolineJean wants any of your solutions, she wants to understand and none of you are helping by giving steps out...
@hartnn yeah, thanks :)
oops just forgot the \(\pm\)
Now take the square root. What do you get?
I don't think you HAVE to simplify...
I dunno it's how I learn. sorry. I will leave.
wow thanks everyone that helped alot :O i have a test tomorrow & didn't know how to do this type of problem but i understand now, thanks ^.^
you go hartn !
Ohh you understand? :) Good :) .
omg the whole time i was trying to figure out how to do it i was trying to figure out how everyone was getting 20... i feel dumb now.... x)
Haha :) .
if you are following my (huge list) of steps. just don't forget to take bot the positive and negative root. So you should get \(x=-2i\sqrt{5}-5\) and \(x=2i\sqrt{5}-5\)
x=.... OR x=... either of them is a solution, not both
yay ! i got that ! @richyw
thank you to the only 2 ppl that really explained what to do lol @hartnn @richyw
Not me? ;) . Jk Jk . Glad you understood :) .
sorry didn't see yours ! :O @Dido525

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