Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Can someone explain to me, STEP BY STEP how to do this problem please, its Algebra 2Complex numbers. 6(x+5)^2=120
 one year ago
 one year ago
Can someone explain to me, STEP BY STEP how to do this problem please, its Algebra 2Complex numbers. 6(x+5)^2=120
 one year ago
 one year ago

This Question is Closed

hartnnBest ResponseYou've already chosen the best response.2
first divide both sides by 6 what u get ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
and u should know that \(\huge \sqrt{1}=i\)
 one year ago

matrickedBest ResponseYou've already chosen the best response.0
6(x+5)^2+120 = (x+5)^2  20i^2 =0 ( and then factorise ) as i^2 =1
 one year ago

1on1Best ResponseYou've already chosen the best response.0
hartn good explanation and asking for participation . well done !!
 one year ago

richywBest ResponseYou've already chosen the best response.1
\[6(x+5)^2=120\]\[(x+5)^2=\frac{120}{6}\]\[x+5=\sqrt{\frac{120}{6}}\]\[x+5=\sqrt{20}\]\[x=\sqrt{20}5\]\[x=\sqrt{20}i5\]\[x=\sqrt{4\cdot 5}i5\]x=2\sqrt{5}i5
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Now take the square root of the RHS .
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Don't just post the answer...
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
i don't think @CarolineJean wants any of your solutions, she wants to understand and none of you are helping by giving steps out...
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
@hartnn yeah, thanks :)
 one year ago

richywBest ResponseYou've already chosen the best response.1
oops just forgot the \(\pm\)
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Now take the square root. What do you get?
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
I don't think you HAVE to simplify...
 one year ago

richywBest ResponseYou've already chosen the best response.1
I dunno it's how I learn. sorry. I will leave.
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
wow thanks everyone that helped alot :O i have a test tomorrow & didn't know how to do this type of problem but i understand now, thanks ^.^
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Ohh you understand? :) Good :) .
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
omg the whole time i was trying to figure out how to do it i was trying to figure out how everyone was getting 20... i feel dumb now.... x)
 one year ago

richywBest ResponseYou've already chosen the best response.1
if you are following my (huge list) of steps. just don't forget to take bot the positive and negative root. So you should get \(x=2i\sqrt{5}5\) and \(x=2i\sqrt{5}5\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
x=.... OR x=... either of them is a solution, not both
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
yay ! i got that ! @richyw
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
thank you to the only 2 ppl that really explained what to do lol @hartnn @richyw
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Not me? ;) . Jk Jk . Glad you understood :) .
 one year ago

CarolineJeanBest ResponseYou've already chosen the best response.0
sorry didn't see yours ! :O @Dido525
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.