anonymous
  • anonymous
Any help? I'm not so familiar with the pounds and feet...would be easier for me to have N and cm A force of 7 pounds is required to hold a spring stretched 0.2 feet beyond its natural length. How much work is done in stretching the spring from its natural length to 1 feet beyond its natural length? Don't forget to enter the correct units. (You may enter lbf or lb*ft for ft-lb.)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
it will be the same thing, what is the formula for work here?
anonymous
  • anonymous
@ Unam
anonymous
  • anonymous
@mark_o. W, F=kx

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
hi my pc got froze.... :D
anonymous
  • anonymous
if F=-kx \[W=\int\limits_{}^{}F(x) dx\]
anonymous
  • anonymous
\[W=\int\limits_{x _{i}}^{x _{f}} -Kx dx\] \[W=-K[\frac{ x ^{2} }{ 2 }]_{x _{i}}^{x _{f}}\] \[W=-\frac{ K }{ 2 }[x ^{2}-x _{f}^{2}]\]
anonymous
  • anonymous
if the initial x=0 then \[W=-\frac{ K }{ 2 }(x _{f})^{2}\]
anonymous
  • anonymous
can you try to do it ?
anonymous
  • anonymous
@ Unam .... :D take care now :D
anonymous
  • anonymous
oh got it
anonymous
  • anonymous
sorry internet was out
anonymous
  • anonymous
just got back..but thanks alot for the help
anonymous
  • anonymous
i have the formula but just cos its in pounds and ft so i'm not familiar with the stuff
anonymous
  • anonymous
F=kx pound F= K x (in ft) then k=lb/ft = pound per foot now work w= -(k/2)x^2 W= (lb / ft)(ft)^2=lb ft
anonymous
  • anonymous
did solve W=? is it 7/4 ft lbs ?
anonymous
  • anonymous
@mark_o. nope :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.