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Study23
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Derivatives, Chain Rule, Numero 3 (Please help!):
\(\ G(x)=(3x2)^{10} (5x^2x+1)^{12} \)
 2 years ago
 2 years ago
Study23 Group Title
Derivatives, Chain Rule, Numero 3 (Please help!): \(\ G(x)=(3x2)^{10} (5x^2x+1)^{12} \)
 2 years ago
 2 years ago

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studentphy Group TitleBest ResponseYou've already chosen the best response.0
10(3x2)^9*3*(5x.....)+(3x...)*12(5x..)^11.(10x1)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
So take the power rule and then use the product rule?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Cool! Thank you @studentphy
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Product rule THEN power rule on each term that requires differentiation :O Just thought I'd mention that in case there was any confusion <:o
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I just got stuck on that problem again. Thanks for the clarification, yet again, @zepdrix!!
 2 years ago

studentphy Group TitleBest ResponseYou've already chosen the best response.0
d/dx(u*V)=keep u constant * derivative of v (which is use power rule)+keep v constant *derivative of U(which is first use power rule then product) hope it clarifies.
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Wait a minute.... How can you differentiate the two terms with exponents when using the product rule before power...? Could someone show me step by step please
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1352354812852:dw
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
\(\ \Huge \text{ Eureka!} \) \(\ \large \text{Thanks for clarifying, that makes sense!} \)
 2 years ago

studentphy Group TitleBest ResponseYou've already chosen the best response.0
suppose u have x^n *2Y then d/dx= nx?^n1* 2Y+ 2(which is after differentiating y )* X^n
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Grrr you and your fancy latex! >:3
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
\(\ \text{Hahaha zepdrix! I actually wasn't all that good when I joined OS 6 month ago.}\) \(\ \text{I've practiced a lot, and look at the latex of other people  which is how I learned.} \) \(\ \text{I'm still learning new things. Practice makes perfect!} \) \(\ \text{ I recently learned how to write text in LATEX. You can be fancy too, with practice!}\)
 2 years ago
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