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Study23
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Derivatives, Chain Rule, Numero 3 (Please help!):
\(\ G(x)=(3x2)^{10} (5x^2x+1)^{12} \)
 one year ago
 one year ago
Study23 Group Title
Derivatives, Chain Rule, Numero 3 (Please help!): \(\ G(x)=(3x2)^{10} (5x^2x+1)^{12} \)
 one year ago
 one year ago

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studentphy Group TitleBest ResponseYou've already chosen the best response.0
10(3x2)^9*3*(5x.....)+(3x...)*12(5x..)^11.(10x1)
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
So take the power rule and then use the product rule?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Cool! Thank you @studentphy
 one year ago

studentphy Group TitleBest ResponseYou've already chosen the best response.0
Most WC
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Product rule THEN power rule on each term that requires differentiation :O Just thought I'd mention that in case there was any confusion <:o
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I just got stuck on that problem again. Thanks for the clarification, yet again, @zepdrix!!
 one year ago

studentphy Group TitleBest ResponseYou've already chosen the best response.0
d/dx(u*V)=keep u constant * derivative of v (which is use power rule)+keep v constant *derivative of U(which is first use power rule then product) hope it clarifies.
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Wait a minute.... How can you differentiate the two terms with exponents when using the product rule before power...? Could someone show me step by step please
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
dw:1352354812852:dw
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
\(\ \Huge \text{ Eureka!} \) \(\ \large \text{Thanks for clarifying, that makes sense!} \)
 one year ago

studentphy Group TitleBest ResponseYou've already chosen the best response.0
suppose u have x^n *2Y then d/dx= nx?^n1* 2Y+ 2(which is after differentiating y )* X^n
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Grrr you and your fancy latex! >:3
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
\(\ \text{Hahaha zepdrix! I actually wasn't all that good when I joined OS 6 month ago.}\) \(\ \text{I've practiced a lot, and look at the latex of other people  which is how I learned.} \) \(\ \text{I'm still learning new things. Practice makes perfect!} \) \(\ \text{ I recently learned how to write text in LATEX. You can be fancy too, with practice!}\)
 one year ago
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