## Study23 Group Title Derivatives, Chain Rule, Numero 3 (Please help!): $$\ G(x)=(3x-2)^{10} (5x^2-x+1)^{12}$$ one year ago one year ago

1. studentphy

10(3x-2)^9*3*(5x.....)+(3x...)*12(5x..)^11.(10x-1)

2. Study23

So take the power rule and then use the product rule?

3. studentphy

yes

4. Study23

Cool! Thank you @studentphy

5. studentphy

Most WC

6. zepdrix

Product rule THEN power rule on each term that requires differentiation :O Just thought I'd mention that in case there was any confusion <:o

7. Study23

I just got stuck on that problem again. Thanks for the clarification, yet again, @zepdrix!!

8. studentphy

d/dx(u*V)=keep u constant * derivative of v (which is use power rule)+keep v constant *derivative of U(which is first use power rule then product) hope it clarifies.

9. Study23

Wait a minute.... How can you differentiate the two terms with exponents when using the product rule before power...? Could someone show me step by step please

10. zepdrix

|dw:1352354812852:dw|

11. Study23

$$\ \Huge \text{ Eureka!}$$ $$\ \large \text{Thanks for clarifying, that makes sense!}$$

12. studentphy

suppose u have x^n *2Y then d/dx= nx?^n-1* 2Y+ 2(which is after differentiating y )* X^n

13. zepdrix

Grrr you and your fancy latex! >:3

14. Study23

$$\ \text{Hahaha zepdrix! I actually wasn't all that good when I joined OS 6 month ago.}$$ $$\ \text{I've practiced a lot, and look at the latex of other people - which is how I learned.}$$ $$\ \text{I'm still learning new things. Practice makes perfect!}$$ $$\ \text{ I recently learned how to write text in LATEX. You can be fancy too, with practice!}$$