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Study23

  • 3 years ago

Derivatives, Chain Rule, Numero 3 (Please help!): \(\ G(x)=(3x-2)^{10} (5x^2-x+1)^{12} \)

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  1. studentphy
    • 3 years ago
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    10(3x-2)^9*3*(5x.....)+(3x...)*12(5x..)^11.(10x-1)

  2. Study23
    • 3 years ago
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    So take the power rule and then use the product rule?

  3. studentphy
    • 3 years ago
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    yes

  4. Study23
    • 3 years ago
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    Cool! Thank you @studentphy

  5. studentphy
    • 3 years ago
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    Most WC

  6. zepdrix
    • 3 years ago
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    Product rule THEN power rule on each term that requires differentiation :O Just thought I'd mention that in case there was any confusion <:o

  7. Study23
    • 3 years ago
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    I just got stuck on that problem again. Thanks for the clarification, yet again, @zepdrix!!

  8. studentphy
    • 3 years ago
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    d/dx(u*V)=keep u constant * derivative of v (which is use power rule)+keep v constant *derivative of U(which is first use power rule then product) hope it clarifies.

  9. Study23
    • 3 years ago
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    Wait a minute.... How can you differentiate the two terms with exponents when using the product rule before power...? Could someone show me step by step please

  10. zepdrix
    • 3 years ago
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    |dw:1352354812852:dw|

  11. Study23
    • 3 years ago
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    \(\ \Huge \text{ Eureka!} \) \(\ \large \text{Thanks for clarifying, that makes sense!} \)

  12. studentphy
    • 3 years ago
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    suppose u have x^n *2Y then d/dx= nx?^n-1* 2Y+ 2(which is after differentiating y )* X^n

  13. zepdrix
    • 3 years ago
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    Grrr you and your fancy latex! >:3

  14. Study23
    • 3 years ago
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    \(\ \text{Hahaha zepdrix! I actually wasn't all that good when I joined OS 6 month ago.}\) \(\ \text{I've practiced a lot, and look at the latex of other people - which is how I learned.} \) \(\ \text{I'm still learning new things. Practice makes perfect!} \) \(\ \text{ I recently learned how to write text in LATEX. You can be fancy too, with practice!}\)

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